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Burka [1]
3 years ago
9

Which of the following is the value of sin^-1(squareroot of 2/2)

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0

Answer:

Quit

Step-by-step explanAation:

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Need help ASAP! Anyone know?
VARVARA [1.3K]

Answer: x= 29°

Step-by-step explanation: Add angles D and C. Subtract from 180.

58/2 = 29

6 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
One common factor of two numbers is 40. Another common factor is 10. If both numbers are less than 100, what are the two numbers
Viefleur [7K]
Only two numbers less than 100 have a factor of 40: 40 (1 x 40) and 80 (2 x 40). Since 40 is a factor of both 40 and 80, 10 must also be a factor - indeed, 40 = 4 x 10 and 80 = 8 x 10.

The two number must be 40 and 80.
5 0
4 years ago
Does anybody know this??????
aniked [119]
The correct answer is 196 or Option A.
The explanation is just as complicated as the question.
7 0
3 years ago
Read 2 more answers
Can someone please answer this and explain it?
professor190 [17]

Answer:

Velocity = displacement / time

Distance = 3t^2 +2t +6 to find distance you need to plug in time = 2 sec

Distance = 3(2)^2 +2(2) +6

Distance = 3(4) +4 + 6

Distance = 12 + 4 +6

Distance = 22 meters

In this problem the displacement is the distance.

so

Velocity = 22 meters / 2 second

Velocity = 11 meters/second

Does this help?

Step-by-step explanation:

4 0
3 years ago
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