9514 1404 393
Explanation:
1. ∠BAC ≅ ∠BCA, BD ≅ BE, ∆BDA and ∆BEC are right triangles . . . . given
2. ∆ABC is isosceles . . . . definition of isosceles triangle
3. BA ≅ BC . . . . definition of isosceles triangle
4. ∆BDA ≅ ∆BEC . . . . HL theorem
5. AC ≅ CE . . . . CPCTC
<u>During the first hour</u> . . .
5% of the 1,000 bacteria die. At the end of the hour, 95% of them are left.
95% of 1,000 = 950
Then 100 are added : 950 + 100 = 1,050
<em>1,050</em> bacteria swimming around in the soup as the second hour begins.
<u>During the second hour</u> . . .
5% of the 1,050 bacteria die. At the end of the hour, 95% of them are left.
95% of 1,050 = 997.5
Then 100 are added : 997.5 + 100 = 1,097.5 . . . . . <em>1,098</em> rounded
===================================
<u>Playing with this some more</u>:
If the same process continues, and the result at the end of each hour
is rounded to the nearest whole number, then the number of bacteria
steadily increases, but only for 88 hours. At the end of the 88th hour,
there are 1991 of the little critters, and after that, the population stays
constant at 1991. That's because the 5% loss during each hour after
that is (5% of 1,991) = 99.55 , which rounds to 100, and those are
replaced by the 100 new ones.
John's gross monthly salary is $2000.
John receives a 15% raise in his salary.
So first we have to find 15% of $2000.
15% of 2000 = 
= 
= 
= 
John's salary including the raise = $
= $2300.
Now 30% of his monthly paycheck withheld for taxes.
30% of 2300 = 
= 
= 
= 
So the amount of tax deducted = $690.
John's net monthly income = $
= $1610.
So we have got the required answer.
Answer:
525
Step-by-step explanation:
This is a question involving combinatorics
The number of ways of choosing a subset k from a set of n elements is given by
which evaluates to 
n! is the product n × (n-1) × (n-2) x....x 3 x 2 x 1
For example,
4! = 4 x 3 x 2 x 1 = 24
3! = 3 x 2 x 1 = 6
Since we have to choose 4 boys from a class of 6 boys, the total number of ways this can be done is

Note that 6! = 6 x 5 x 4 x 3 x 2 x 1 and 4 x 3 x 2 x 1 is nothing but 4!
So the numerator can be re-written as 6 x 5 x (4!)
We can rewrite the expression 
Cancelling 4! from both numerator and denominator gives us the result
as (6 × 5)/2! = 20/2 = 15 different ways of choosing 4 boys from a class of 6 boys
For the girls, the number of ways of choosing 3 girls from a class of 7 girls is given by

This works out to (7 x 6 x 5 )/(3 x 2 x 1) (using the same logic as for the boys computation)
= 210/6 = 35
So total number of committees of 4 boys and 3 girls that can be formed from a class of 6 boys and 7 girls = 15 x 35 = 525
Answer:
Youre answer is 12.5%
Step-by-step explanation:
Percent change is calculated as
Change original×100%
Change =32−28=4 pages
=4
1328×100%=1008%=
And then your final answer:
12.5%
Glad I could help, hv a good day :3