Help really quick and fast plzzzzzz

The sum of the exterior angles of a polygon is always 180 degrees. True or False

Bezzdna [24]

False. it said ,"The sum of the exterior angles of a polygon is always 360 degrees. ... By an inductive proof, this is true for all polygons." that is what i think.

5 0

3 years ago

Read 2 more answers

Calculate the speed for a car that went a distance of 125 kilometers in 2 hours time.

IrinaVladis [17]

125÷2=67.5

67.5+67.5=125

4 0

2 years ago

9x-6+11x what would the answer be

frez [133]

Answer:

20x-6

Step-by-step explanation:

5 0

3 years ago

The shoe store's clerks are paid on commission. If the clerk receives a 12% commission on total purchase amounts before tax is a

aev [14]

Answer:

a) 37 + 42 =79

=7/100 x 79

=553/100

=5.53

Isaac's total bill = 79 + 5.53 = $84.53

b) 25/100 x 79

= 19.75

= 79 - 19.75

= $59.25 (before tax)

7/100 x 59.25

= 414.75/100

= 4.15

= 59.25 + 4.15

= $63.4 (after adding tax)

First we have to take out the percentage of discount and minus it from the total cost . To find the discounted price with tax, we have to take out the percentage of the tax from the discounted amount and add it to the discounted amount to get the total cost.

3 0

3 years ago

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti

melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that $m = 100, \mu = \frac{1}{100} = 0.01$

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

$P(X > x) = e^{-\mu x}$

This is P(X > 190). So

$P(X > 190) = e^{-0.01*190} = 0.1496$

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

$P(X > x) = 0.08$