Guys please help me out these
2 answers:
Answer:
l (PM): y = -2/3x + 2
y-coordinate: -1
Step-by-step explanation:
B (x, y): (x+1)/2 = 3 x = 5
(y + -2) / 2 = 1 y = 4 ... B (5,4)
slope of AB = (4- -2)/(5-1) = 3/2
PM bisect AB, PM⊥ AB
slope of AB = - 2/3
equation of PM : (y-1)/(x-3) = -2/3
y-1=-2/3x+2
<u>y = -2/3x+3</u>
PA = PB = radius P (6,k)
PA² = PB² ... (6-1)²+(k- -2)² = (6-5)²+(k-4)²
25+k²+4k+4 = 1+k²-8k+16 ... -K² both side
12k = -12 <u>k = -1</u>
P (6 , -1) r = √(6-1)²+(k- -2)² = √(6-1)²+(-1- -2)² = √26
equation of circle: (x-h)² + (y-k)² = r² .. h=6, k=-1, r=√26
I'm sure you can figure out the equation by yourself... :)
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Answer:
Step-by-step explanation:
Your equation is:
You also know that x = -3 and y = 2. You can rewrite the equation by substituting x and y with their actual values:
First, you want to do the exponentiation (meaning you want to calculate and
parts).
equals 9 and
equals 16.
So the equation now is:
Now you want to do multiplication. equals 36 and
equals 32. So you're left with:
Which equals 68.