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mojhsa [17]
1 year ago
14

Which product is a negative

Mathematics
1 answer:
natka813 [3]1 year ago
7 0

Answer:

c is negative

Step-by-step explanation:

when multiplied c is negative

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Can you plz solve this ​
Lesechka [4]

Answer:

a) acute angle

b) obtuse angle

c) right angle

d) reflex angle

e) straight line angle

f) acute angle

Step-by-step explanation:

Acute angle

  • angle that is smaller than 90°
  • 0° < θ < 90°

Right angle

  • angle that is 90°
  • shaped of a "L"

Obtuse angle

  • angle that is greater than 90° but smaller than 180°
  • 90° < θ < 180°

Straight line angle

  • angle that is 180°
  • drawn in a straight line

Reflex angle

  • angle than is greater than 180°
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8 0
3 years ago
Choose the correct answer.
Morgarella [4.7K]

Answer: Oh the answer is 30.00

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Chioe stops for lunch in a town that
Rainbow [258]
C $15.75 E $15.95 And B $16.25 those there the answers
4 0
2 years ago
we choose a sample of size 100 from a population of monthly cable bills having standard deviation $20 If we assume the populatio
igor_vitrenko [27]

Answer:

0.0062

Step-by-step explanation:

Find the standard error.

σ = 20 / √100

σ = 2

Find the z-score.

z = (x − μ) / σ

z = (70 − 65) / 2

z = 2.5

Find the probability.

P(Z > 2.5) = 1 − 0.9938

P(Z > 2.5) = 0.0062

8 0
2 years ago
A ball is thrown vertically upward from the top of a building 160 feet tall with an initial velocity of 48 feet per second. The
alina1380 [7]

Answer:

# after 5 seconds, the ball strikes the ground

# The ball reaches maximum height at t = 1.5 seconds

# The max height is 196 feet

Step-by-step explanation:

The equation is:

d(t)=-16t^2+48t+160

t is the time

d(t) is the distance traveled

Initial height is 160 feet and initial velocity is 48 ft/sec

If we want to find the time it takes the ball to hit the ground, we let d(t) equal to 0 and find t. Shown below:

-16t^2+48t+160=0\\t^2-3t-10=0\\(t-5)(t+2)=0\\t=5,-2

We disregard t = -2 since time can't be negative. We take t = 5

Thus, after 5 seconds, the ball strikes the ground.

The equation is a quadratic of the form: ax^2+bx+c

Matching equations, we can say:

a = -16

b = 48

c = 160

The time when ball reaches max height is given as:

t=-\frac{b}{2a}

Substituting, we find:

t=-\frac{b}{2a}\\t=-\frac{48}{2(-16)}\\t=1.5

The ball reaches maximum height at t = 1.5 seconds

The max height can be found by putting t = 1.5 into the original equation. Shown below:

d(t)=-16t^2+48t+160\\d(1.5)=-16(1.5)^2+48(1.5)+160\\=196

The max height is 196 feet

8 0
3 years ago
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