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3 years ago

What is the most important criteria for a sample to be considered unbiased?

Mathematics

2 answers:

Aloiza [94]3 years ago

7 0

Answer:

Sampling Criteria is one must remember that two costs are involved in a sampling analysis viz., the cost of collecting the data and the cost of an incorrect inference resulting from the data. Researcher must keep in view the two causes of incorrect inferences viz., systematic bias and sampling error.

zysi [14]3 years ago

5 0

Answer:

A sample drawn and recorded by a method which is free from bias. This implies not only freedom from bias in the method of selection, e.g. random sampling, but freedom from any bias of procedure, e.g. wrong definition, non-response, design of questions, interviewer bias, etc.

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1. Consider an athlete running a 40-m dash. The position of the athlete is given by , where d is the position in meters and t is

sasho [114]

There is some information missing in the question, since we need to know what the position function is. The whole problem should look like this:

Consider an athlete running a 40-m dash. The position of the athlete is given by $d(t)=\frac{t^{2}}{6}+4t$ where d is the position in meters and t is the time elapsed, measured in seconds.

Compute the average velocity of the runner over the intervals:

(a) [1.95, 2.05]

(b) [1.995, 2.005]

(d) [2, 2.00001]

Answer

(a) 6.00041667m/s

(b) 6.00000417 m/s

(d) 6.00001 m/s

The instantaneous velocity of the athlete at t=2s is 6m/s

Step by step Explanation:

In order to find the average velocity on the given intervals, we will need to use the averate velocity formula:

$V_{average}=\frac{d(t_{2})-d(t_{1})}{t_{2}-t_{1}}$

so let's take the first interval:

(a) [1.95, 2.05]

$V_{average}=\frac{d(2.05)-d(1.95)}{2.05-1.95}$

we get that:

$d(1.95)=\frac{(1.95)^{3}}{6}+4(1.95)=9.0358125$

$d(2.05)=\frac{(2.05)^{3}}{6}+4(2.05)=9.635854167$

so:

$V_{average}=\frac{9.6358854167-9.0358125}{2.05-1.95}=6.00041667m/s$

(b) [1.995, 2.005]

$V_{average}=\frac{d(2.005)-d(1.995)}{2.005-1.995}$

we get that:

$d(1.995)=\frac{(1.995)^{3}}{6}+4(1.995)=9.30335831$

$d(2.005)=\frac{(2.005)^{3}}{6}+4(2.005)=9.363335835$

so:

$V_{average}=\frac{9.363335835-9.30335831}{2.005-1.995}=6.00000417m/s$

$V_{average}=\frac{d(2.0005)-d(1.9995)}{2.0005-1.9995}$

we get that:

$d(1.9995)=\frac{(1.9995)^{3}}{6}+4(1.9995)=9.33033358$

$d(2.0005)=\frac{(2.0005)^{3}}{6}+4(2.0005)=9.33633358$

so:

$V_{average}=\frac{9.33633358-9.33033358}{2.0005-1.9995}=6.00000004m/s$

(d) [2, 2.00001]

$V_{average}=\frac{d(2.00001)-d(2)}{2.00001-2}$

we get that:

$d(2)=\frac{(2)^{3}}{6}+4(2)=9.33333333$

$d(2.00001)=\frac{(2.00001)^{3}}{6}+4(2.00001)=9.33339333$

so:

$V_{average}=\frac{9.33339333-9.33333333}{2.00001-2}=6.00001m/s$

Since the closer the interval is to 2 the more it approaches to 6m/s, then the instantaneous velocity of the athlete at t=2s is 6m/s

8 0

3 years ago

What are the solutions to the quadratic equation x2 – 16 = 0?

exis [7]

Answer:

2nd choice: x=4 and x=-4

Step-by-step explanation:

x^2 - 16 = 0 can be simplified to (x-4)(x+4)=0

x-4 = 0 so x = 4

and x + 4 = 0 so x = -4

4 0

3 years ago

Read 2 more answers

The image shows parallel lines cut by a transversal. The expressions represent unknown angle measurements. What is the value of

Anna35 [415]

Answer:

x = 8

Step-by-step explanation:

5 0

3 years ago

Sally needs 2/3 of a pound of potatoes. This is 1/3 of a pound more than 4/3 of the potatoes Sally has in her pantry

amid [387]

Lets assume, Sally has X pound of potatoes in her pantry.

So, 4/3 of the potatoes Sally has in her pantry = $\frac{4}{3}X$

Now, Sally needs 2/3 pound of potatoes and this 2/3 pound of potatoes is 1/3 pound more than that $\frac{4}{3}X$

So the representing equation will be:

$\frac{2}{3} = \frac{1}{3}+ \frac{4}{3}X$

$\frac{2}{3} - \frac{1}{3} = \frac{4}{3} X$ (subtracting $\frac{1}{3}$ from both sides)

$\frac{1}{3}= \frac{4}{3}X$

$1= 4X$ (multiplying both sides by 3)

$X =\frac{1}{4}$

So, Sally has $\frac{1}{4}$ pound of potatoes in her pantry.

4 0

3 years ago

Find the sum or difference (10p - 4q^2 - q) - (q^2 - 7p + 9p^2)

marin [14]

Answer:

C) -9p^2 - 5q^2 + 17p - q

Step-by-step explanation:

(10p - 4q^2 - q) - (q^2 - 7p + 9p^2)

10p - 4q^2 - q - q^2 + 7p - 9p^2

10p + 7p - 4q^2 - q^2 -9p^2 - q

17p -5q^2 -9p^2 - q

-9p^2 - 5q^2 + 17p - q

4 0

3 years ago