Answer:
The missing dimension of the prism is (x-4)
Step-by-step explanation:
Here, we want to find the missing dimensions of the prism
To get the volume, we are to multiply three dimensions since we are talking about volume
Mathematically, to find the third dimension, we need to divide the original polynomial by the product of the two other dimensions
The product of the two other dimensions is;
(x-1)(x-9) = x^2-9x-x + 9
= x^2-10x+ 9
So we divide;
(x^3-14x^2+49x-36)/(x^2-10x+ 9)
We can use long division to get this
using long division, the answer here is x-4
Answer:
25 houses on prince street
Step-by-step explanation:
add them up and bam
Ok so this all about subtracting fractions this is what you want to do:
you can change 8 3/4 and 4 2/3 to have the same value and deominator
8 3/4 = 8 9/12(multiply both sides by 3)
4 2/3 = 4 8/12(multiply both sides by 4)
you do this because 12 is divisible by 3 and 4
then, subtract 4 8/12 from 8 9/12 because John is using some of the wood his dad gave him.
then subtract once again, taking 11/2 away from your difference.
again match the deominator of 11/2 to the deominator of your difference which should be 12. another divisible of 12 is 2 and 6.
11/2 = 66/12 = 5 6/12(multiply both the top and bottom by 6)
and start subtracting.
so John should have -1 5/12(?) wood left
Answer:
B
Step-by-step explanation:
Law of Quadrilaterals.
I think this is correct, how it helps.
9514 1404 393
Answer:
D. Both functions are decreasing at the same average rate on that interval
Step-by-step explanation:
The dashed lines on the attached graph of the two functions (f in red, g in purple) represent the average rate of change of each function on the interval. The lines are parallel, because the average rate of change is the same for each of the functions on that interval.
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Function f decreases by 60 units from f(0) = 64 to f(4) = 4 on the interval x = [0, 4]. Function g decreases by 60 units from g(0) = 75 to g(4) = 15 on the same interval. The average rate of change is the amount of decrease divided by the interval width. Those values are the same for both functions.
