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alexandr402 [8]
2 years ago
14

Solve this equation -4/5x+7=-13

Mathematics
2 answers:
ad-work [718]2 years ago
8 0

Answer:

gladly (:

Step-by-step explanation:

-4/5x+7=-13

multiply both sides of the equation by 5

-4x+35=-65

subtract 35 from both sides

-4x=-100

divide both sides of the equation by -4

x=25

Korolek [52]2 years ago
6 0
X = 25
combine multiple terms into a single fraction: 4x/5 + 7 = -13
Find the common denominator
combine the fractions with the denominator

multiply; 5x7
then do that with the terms by the same value

multiply the numbers
subtract 35 from both of the equation
simplify
divide both side by the same term
simplify again,

so it’s 25

IF THIS HELPS SAY THANKS OR MAKE ME THE BRAINIEST ANSWER :)
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Which algebraic expression is a difference with two terms
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Step-by-step explanation:

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a^2 - b^2 is "a difference with two terms."

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3 years ago
A local hamburger shop sold a combined total of 712 hamburgers and cheeseburgers on Tuesday. There were 62 more cheeseburgers so
hammer [34]
A local hamburger shop sold a total of 712 burgers on Tuesday

There are 62 more cheeseburgers than hamburgers

let cheeseburers = c
let hamburgers = h

h + 62 = c
c + h = 712

Plug in h + 62 for c

(h + 62) + h = 712
2h + 62 = 712
2h + 62 (-62) = 712 (-62)
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2h/2 = 650/2
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There are 325 hamburgers sold on Tuesday

c = 325 + 62
c = 387

<em>There are 387 chesseburgers sold on tuesday </em>(in case you were wondering)


hope this helps
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3 years ago
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Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

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