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3 years ago

In a sequence described by a function, what does the notation f(3)=1 mean

Mathematics

2 answers:

lara [203]3 years ago

6 0

Answer with explanation:

If an expression, f(x)=y, is a function, then for every y , there is unique x and for every x, there is unique y.

⇒f(3)=1, means ,when in the expression, x is substituted by, 3 , the value of y is 1.

⇒x(Domain) y(Range)

3 1

The Set of values that x can take is called Domain of the function, and the set of values that y can take is called Range of the function.

vladimir2022 [97]3 years ago

5 0

X = 3
Y = 1

f(3)=1
X Y

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Which equation does this image represent?

nirvana33 [79]

Given:

Image of the ellipse

To find:

The equation of the image

Solution:

The given image is a ellipse.

Center of the ellipse = (0, 0)

x-axis points are (-3, 0) and (3, 0).

y-axis points are (2, 0) and (-2, 0).

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$$\frac{(x-0)^{2}}{3^{2}}+\frac{(y-0)^{2}}{2^{2}}=1$

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To make the denominator same multiply 1st term by $\frac{4}{4}$ and 2nd term by $\frac{9}{9}$ .

$$\frac{4x^{2}}{4\times9}+\frac{9y^{2}}{9\times4}=1$

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$$\frac{4x^{2}+9y^{2}}{36}=1$

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3 years ago

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inysia [295]

Answer:

$S_{n}$ = n² + 4n ; n = 11

Step-by-step explanation:

$S_{n}$ = $\frac{n}{2}$ [2 $a_{1}$ + (n - 1)d]

~~~~~~~~~

$a_{1}$ = 5

d = 7 - 5 = 2

$S_{n}$ = $\frac{n}{2}$ [ 2(5) + 2(n - 1)] = $\frac{n}{2}$ ( 8 + 2n ) = 4n + n²

$S_{n}$  = n² + 4n

n² + 4n = 165

n² + 4n - 165 = 0

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