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Pepsi [2]
2 years ago
5

Express the recurring decimal 1.52 as an improper fraction

Mathematics
2 answers:
Bezzdna [24]2 years ago
7 0
To convert the decimal 1.52 to a fraction, just follow these steps:
Step 1: Write down the number as a fraction of one:
1.52 = 1.52
1
Step 2: Multiply both top and bottom by 10 for every number after the decimal point:
As we have 2 numbers after the decimal point, we multiply both numerator and denominator by 100. So,
1.52
1
= (1.52 × 100)
(1 × 100)
= 152
100
.
Step 3: Simplify (or reduce) the above fraction by dividing both numerator and denominator by the GCD (Greatest Common Divisor) between them. In this case, GCD(152,100) = 4. So,
(152÷4)
(100÷4)
= 38
25
when reduced to the simplest form.
As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 152
100
is also
ElenaW [278]2 years ago
5 0

(152÷4)(100÷4) = 3825 when reduced to the simplest form. As the numerator is greater than the denominator, we have an IMPROPER fraction, so we can also express it as a MIXED NUMBER, thus 152100 is also equal to 11325 when expressed as a mixed number.

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Given that P = (-5, 5) and Q = (-13, 10), find the component form and magnitude of 2 vector PQ.
Brut [27]
Define unit vectors along the x-axis and the y-axis as \hat{i} , \, \hat{j} respectively.

Then the vector from P to Q is
\vec{PQ} = (-13+5)\hat{i} + (10-5)\hat{j} = -8\hat{i} + 5\hat{j}
In component form, the vector PQ is (-8,5).

The magnitude of vector PQ is
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Answer:
The vector PQ is (-8, 5) and its magnitude is √89  (or 9.434).
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