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Inga [223]
2 years ago
10

A quadrilateral with exactly two parallel lines is a

Mathematics
1 answer:
Troyanec [42]2 years ago
4 0

Step-by-step explanation:

(parallelogram) is the homogeneous mixture

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Four glasses of milk and 2 snack bars have a total of 72 carbohydrates​ (carbs), and 2 glasses of milk and 3 snack bars have a t
Travka [436]

One glass of milk has 11 carbs and one snack bar has 14 carbs.

Step-by-step explanation:

Let,

Glass of milk = x

Snack bar = y

According to given statement;

4x+2y=72   Eqn 1

2x+3y=64   Eqn 2

Multiplying Eqn 2 by 2

2(2x+3y=64)\\4x+6y=128\ \ \ Eqn\ 3

Subtracting Eqn 1 from Eqn 3

(4x+6y)-(4x+2y)=128-72\\4x+6y-4x-2y=56\\4y=56

Dividing both sides by 4

\frac{4y}{4}=\frac{56}{4}\\y=14

Putting y=14 in Eqn 1

4x+2(14)=72\\4x+28=72\\4x=72-28\\4x=44

Dividing both sides by 4

\frac{4x}{4}=\frac{44}{4}\\x=11

One glass of milk has 11 carbs and one snack bar has 14 carbs.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/5461619
  • brainly.com/question/5510873

#LearnwithBrainly

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Read 2 more answers
Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.
Gnesinka [82]

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, \overline{CP} ⊥ \overline{AM}, AP = 9, and PM = 16

\overline{AC}² + \overline{CM}² = \overline{AM}²

\overline{AM} = \overline{AP} + PM = 9 + 16 = 25

\overline{AM} = 25

\overline{AC}² = \overline{AP}² + \overline{CP}² = 9² +  \overline{CP}²

∴ \overline{AC}² = 9² +  \overline{CP}²

Similarly we get;

\overline{CM}² = 16² + \overline{CP}²

Therefore, we get;

\overline{AC}² + \overline{CM}² = 9² +  \overline{CP}² + 16² + \overline{CP}² = \overline{AM}² = 25²

2·\overline{CP}² = 25² - (9² + 16²) = 288

\overline{CP}² = 288/2 = 144

\overline{CP} = √144 = 12

From \overline{AC}² = 9² +  \overline{CP}², we get

\overline{AC} = √(9² +  12²) = 15

\overline{AC} = 15

From, \overline{CM}² = 16² + \overline{CP}², we get;

\overline{CM} = √(16² + 12²) = 20

\overline{CM} = 20.

3 0
2 years ago
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