You have to multiply both numbers with the same factor. What I mean, 475/58 gives you 8 R 11. Now let's try this, (475x2=950) and (58x2= 116) so our new numbers are 950/116 which gives us the same answer 8 R 11 ! I hope this helped.. But let's try another one, keep in mind, you can multiply the number by any factor AS LONG AS you multiply them with the SAME factor. So if you multiply 475 by 5, then you have to multiply the 58 by 5 as well. Now let's try, (475x5=2375) and (58x5= 290) therefore, 2375/290 = which gives you 8 R 11 ! I hope I helped . I am a Palestinian student in Palestine in grade 11 and you just brought me back to grade 4 memories ! math is fun when you get it (: good luck
Answer:
12 hope this help out dude
1) Given: ds / dt = 3t^2 / 2s
2) Separate variables: 2s ds = 3t^2 dt
3) Integrate both sides:
∫ 2s ds = ∫ 3t^2 dt
s^2 + constant = t^3 + constant
=> s^2 = t^3 + constant
=> s = √ (t^3 + constant)
Answer: option B.
Answer:
-4, 3 I think that correct but I'm not sure so sorry if it's not
Step-by-step explanation:
Complete question :
a ladder 5 meters long is leaning against a wall. the base of the ladder is sliding away from the wall at a rate of 1 meter per second. how fast is the top of the ladder sliding down the wall at the instant when the base is 4 meters from the wall?
Answer:
-4/3 m/s
Step-by-step explanation:
Using Pythagoras :
a² = x² + c²
5² = x² + y² - - - (1)
The horizontal distance x with respect to time t = 1m/sec
dx/dt = 1m/sec
To obtain the vertical height 'y' with respect to time t when x = 4
5² = x² + y²
Wen x = 4
5² = 4² + y²
25 = 16 + y²
y =√(25 - 16)
y = 3
Differentiate (1) with respect to t
x² + y² = 25 - ---- - (1)
2x * dx /dt + 2y dy/dt = 0
dx/dt = 1
x = 4.
y = 3
2(4)(1) + 2(3) * dy/dt = 0
8 + 6dy/dt = 0
6 dy/dt = - 8
dy/dt = - 8/6
dy/dt = - 4/3
