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3 years ago

Find the constant of proportionality in the graph

Mathematics

1 answer:

pshichka [43]3 years ago

7 0

The answer is B. Since the graph increases by 4 on the y-axis as x increases by 1, the constant of proportionality is 4.

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2r-7=-1. Help please thanks

UkoKoshka [18]

Answer:

-3

Step-by-step explanation:

6 0

3 years ago

Solve y = mx + b for x

eimsori [14]

Y=mx+b
-b -b
--------------
-by= mx
-------------
m m

-by
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m

8 0

3 years ago

3≤7+g Another solution one :) What is the solution?

gizmo_the_mogwai [7]

Answer:

Inequality Form:

g ≥ − 4

Interval Notation:

[ − 4 , ∞ )

Step-by-step explanation:

Solve for g by simplifying both sides of the inequality, then isolating the variable.

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3 years ago

25+29=9v solve for v

Natasha_Volkova [10]

The answer is V= 6 :)

8 0

3 years ago

Read 2 more answers

I need help with this problem

Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒ $cosA=\frac{u.v}{|u||v|}$

Given u=-8i-3j and v=-8i+8j

$|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544$

$|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137$

let A be angle before u and v

therefore, $cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}$

⇒ $A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56$

Therefore angle between u and v is 65.56°

5 0

3 years ago