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Daniel [21]
3 years ago
15

Evaluate the surfacuse stokes's theorem to evaluate f · dr

Mathematics
1 answer:
Alik [6]3 years ago
7 0
Since you're asked to use Stoke's theorem, I'm interpreting the question to be asking to compute the line integral

\displaystyle\int_{\mathcal C}\mathbf f(x,y,z)\cdot\mathrm d\mathbf r

which by Stoke's theorem is equivalent to the surface integral

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f(x,y,z)\cdot\mathrm d\mathbf S

where \mathcal S is the positively-oriented surface with boundary \mathcal C.

Given \mathbf f(x,y,z)=2y\,\mathbf i+3z\,\mathbf j+x\,\mathbf k, we get curl

\nabla\times\mathbf f=-3\,\mathbf i-\mathbf j-2\,\mathbf k

We parameterize the surface \mathcal S by

\mathbf s(u,v)=5(1-u)(1-v)\,\mathbf i+5u(1-v)\,\mathbf j+5v\,\mathbf k

with 0\le u\le1 and 0\le v\le1. Then we take the partial derivatives of \mathbf s and check their cross product:

\mathbf s_u\times\mathbf s_v=25(1-v)(\mathbf i+\mathbf j+\mathbf k)

Now,

\mathrm d\mathbf S=(\mathbf s_u\times\mathbf s_v)\,\mathrm du\,\mathrm dv

so the surface integral reduces to

\displaystyle-150\int_{v=0}^{v=1}\int_{u=0}^{u=1}(1-v)\,\mathrm du\,\mathrm dv=-75
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Step-by-step explanation:

Since it is given that we have 2 pairs of two parallel sides, which implies 4 sides, this thus shows that the shape is a quadrilateral since, only quadrilaterals have 4 sides. Also, 2 pairs of sides are the same length, and are parallel, it shows that the shape is likely a rectangle.

Finally, there are 4 square corners on the shape which implies 4 right angles. This confirms that our shape is a rectangle since only a rectangle has 2 pairs of two parallel sides and 2 pairs of sides that are the same length there are 4 square corners.

So, the patio is a rectangle.

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Below

Step-by-step explanation:

Angle A= 65 degrees

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