Out of 5 cards in the bag ...
-- There are 2 even numbers . . . 2 and 4 .
-- There are 3 odd numbers . . . 1, 3, and 5 .
So EITHER time, the probability of pulling an even number is 2/5 ,
and the probability of pulling an odd number is 3/5 .
The probability of pulling an even number the first time
AND an odd number the second time is
(2/5) x (3/5) = 6/25 = <em>24%</em> .
Answer:
135
Step-by-step explanation:
15 x 9 = 135
If

is the amount of salt in the tank at time

, then the rate at which this amount changes over time is given by the ODE


We're told that the tank initially starts with no salt in the water, so

.
Multiply both sides by an integrating factor,

:




Since

, we have

so that the amount of salt in the tank over time is given by

After 10 minutes, the amount of salt in the tank is
Hi there!
The answer is:
The range of a relation is the output (y) values of the relation. The range represents the set of the y-coordinates from the ordered pairs.
~ Hope this helps you!
Answer:
495
Step-by-step explanation:
45×10=450
450+45=495