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mafiozo [28]
3 years ago
14

Why is observational learning difficult to explain in terms of operant conditioning?

SAT
2 answers:
kodGreya [7K]3 years ago
8 0

Could be cuz they're different. Observational learning extends the effective range of (both) operant and classical conditioning. During operant conditioning, one learns through (direct) experience. With observational learning you observe how it's done and then you do it. With children and even adults one way may not work.

(positive and negative reinforcement strengthen behavior; punishment, response cost, and extinction weaken behavior).

If I didn't explain it well lmk and I'll try again.

RoseWind [281]3 years ago
4 0

Answer:

Children may not only repeat bad language, but can also learn other negative behaviors, such as aggression, from watching adults. ... American psychologist, Albert Bandura, chose to focus on the how these aggressive behaviors are learned.

Explanation:

pls. mark brainliest plsss ಥ‿ಥ

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If you don't understand something it is a good idea to.
qwelly [4]

You learn new thing every day!!!

Explanation:

5 0
2 years ago
Use series to approximate the definite integral i to within the indicated accuracy. i = 1/2 x3 arctan(x) dx 0 (four decimal plac
Valentin [98]

The expression \int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx  is an illustration of definite integrals

The approximated value of the definite integral is 0.0059

<h3>How to evaluate the definite integral?</h3>

The definite integral is given as:

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx

For arctan(x), we have the following series equation:

\arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1}}{2n + 1}}

Multiply both sides of the equation by x^3.

So, we have:

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1}}{2n + 1}}  * x^3

Apply the law of indices

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1 + 3}}{2n + 1}}

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Evaluate the product

x^3 \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Introduce the integral sign to the equation

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =\int\limits^{1/2}_{0} \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Integrate the right hand side

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}} ]\limits^{1/2}_{0}

Expand the equation by substituting 1/2 and 0 for x

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}} ] - [ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{0^{2n + 4}}{2n + 1}} ]

Evaluate the power

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}} ] - 0

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}}

The nth term of the series is then represented as:

T_n = \frac{(-1)^n}{2^{2n + 5} * (2n + 4)(2n + 1)}

Solve the series by setting n = 0, 1, 2, 3 ..........

T_0 = \frac{(-1)^0}{2^{2(0) + 5} * (2(0) + 4)(2(0) + 1)} = \frac{1}{2^5 * 4 * 1} = 0.00625

T_1 = \frac{(-1)^1}{2^{2(1) + 5} * (2(1) + 4)(2(1) + 1)} = \frac{-1}{2^7 * 6 * 3} = -0.0003720238

T_2 = \frac{(-1)^2}{2^{2(2) + 5} * (2(2) + 4)(2(2) + 1)} = \frac{1}{2^9 * 8 * 5} = 0.00004340277

T_3 = \frac{(-1)^3}{2^{2(3) + 5} * (2(3) + 4)(2(3) + 1)} = \frac{-1}{2^{11} * 10 * 7} = -0.00000634131

..............

At n = 2, we can see that the value of the series has 4 zeros before the first non-zero digit

This means that we add the terms before n = 2

This means that the value of \int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx to 4 decimal points is

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.00625 - 0.0003720238

Evaluate the difference

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.0058779762

Approximate to four decimal places

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.0059

Hence, the approximated value of the definite integral is 0.0059

Read more about definite integrals at:

brainly.com/question/15127807

5 0
2 years ago
FREEEEEEEEEEEEEEEEEE POINNNNNNNNNNNNNTS
rewona [7]

Answer:

thanks for free points

Explanation:

have a great day!!!

7 0
3 years ago
Read 2 more answers
Some organizations set up LANs as ______.
Usimov [2.4K]

Some organizations set up LANs as network server.

<h3>What is network server?</h3>

A network server is designed like a computer this is to help act as store for information where repository are sent.

It also give access to other devices such as disk space and printer where by they can send information from them through the Network server.

There are different network server depending on the function other examples are WAN and MAN

Therefore,

Some organizations set up LANs as network server.

learn more on server below

brainly.com/question/24137718

#SPJ1

8 0
2 years ago
How do biotechnologists help with modern mining methods?
zlopas [31]

Answer: They evaluate the microbes contained in minerals to determine the grade of the ore. They devise methods to kill the microbes in minerals to make the ore more profitable. They look for ways to genetically engineer microbes to aid in obtaining specific minerals.

Explanation:

4 0
2 years ago
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