Answer:
yes
Step-by-step explanation:
Answer:
we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7 psi
Step-by-step explanation:
Let's first define the hypothesis;
Null hypothesis: H0: μ = 4.7
Alternative hypothesis: Ha: μ ≠ 4.7
We have;
Sample size; n = 110
Sample mean; x¯ = 4.6
Variance: σ² = 0.64
Standard deviation; σ = √0.64 = 0.8
Formula for test statistic is;
z = (x¯ - μ)/(σ/√n)
z = (4.6 - 4.7)/(0.8/√110)
z = -0.1/0.0763
z = -1.31
From online p-value from z-score calculator attached, using; z = -1.31, two tailed hypothesis, significance value of 0.1, we have;
P-value = 0.190196
The p-value is greater than the significance value and thus we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7
σ μ
Answer:
7234.56 in³
Step-by-step explanation:
4/3πr³
4/3 (3.14)(12)³
7234.56 in³
Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125
Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50. #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5
Answer:
Distance covered by hula hoop rolls in 4 full rotations is 880 cm .
Step-by-step explanation:
Formula

Where r is the radius of the circle.
As given
Allison is rolling her hula hoop on the playground.
The radius of her hula hoop is 35 cm.
r = 35 cm

Putting the value in the formula

= 220 cm
As given
The hula hoop rolls in 4 full rotations.
Distance covered by hula hoop rolls in 4 full rotations = 220 × 4
= 880 cm
Therefore the Distance covered by hula hoop rolls in 4 full rotations is 880 cm .