Question

Find three consecutive even integers whose sum is 72

Answer 1

Answer:

Let the three consecutive even numbers be x, x + 2 and x + 4

Given, their sum = 72

According to the question,

x + x + 2 + x + 4 = 72

3x + 6 = 72

3x = 72 - 6

3x = 66

x=66/3

x = 22

1st number => x

➾ 22

2nd number => x + 2

=> 22 + 2

➾ 24

3rd number => x + 4

=> 22 + 4

➾ 26

Step-by-step explanation:

Answer 2

The required numbers are 22,24,26.