Find three consecutive even integers whose sum is 72
2 answers:
Answer:
Let the three consecutive even numbers be x, x + 2 and x + 4
Given, their sum = 72
According to the question,
x + x + 2 + x + 4 = 72
3x + 6 = 72
3x = 72 - 6
3x = 66
x=66/3
x = 22
1st number => x
➾ 22
2nd number => x + 2
=> 22 + 2
➾ 24
3rd number => x + 4
=> 22 + 4
➾ 26
Step-by-step explanation:
The required numbers are 22,24,26.
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