All categories

3 years ago

PLSS HELP ME I WILL GIVE BRAINLIEST PLSSS

Mathematics

1 answer:

Firlakuza [10]3 years ago

4 0

Answer: -2

Step-by-step explanation: Perpendicular lines have negative reciprocal slopes. That means the fraction is flipped and multiplied by negative 1.

You might be interested in

Solve the following permutation. 6P3

victus00 [196]

Here, the answer is 120

4 0

3 years ago

Explain pls and thanks

murzikaleks [220]

Starting more simply, if we wanted to know how many students like pink in general, that's 68/100. We could do that for each single category and the fractions would add together to equal 1. Now say we wanted to know something about that 68/100 people. That 68 is our new 100%, or another way of looking at it is if we take however many people like pink and don't like black and those that do like black, they will equal 68/68.

The number of people that like pink but don't like black is 41/68 and those that like pink and black are 27/68. 27+41=68 For the question of your problem it is asking about those that do not like pink which you can tell from the table or use from my saying 68/100 like pink is 32. Now you can split that into those that do or don't like black, and the two results will equal 32/32.

7 0

3 years ago

Square efgh has been reflected across the x axis and then reflected across the y axis which of the following transformations wou

tigry1 [53]

An 180-degreee rotation would return the square to its original position.

6 0

3 years ago

Read 2 more answers

What 2 numbers add to get 2 and multiply to 4

rusak2 [61]

Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x= $\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a}$ so

1x^2-2x+4=0
a=1
b=-2
c=4
x= $\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}$
x= $\frac{ 2+/-\sqrt{4-16} }{2}$
x= $\frac{ 2+/-\sqrt{-12} }{2}$
we have $\sqrt{-12}$ and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x= $\frac{ 2+/-2\sqrt{-3} }{2}$
i= $\sqrt{-1}$
x= $\frac{ 2+/-2i\sqrt{3} }{2}$
x= $1+/-i\sqrt{3}$
x= $1-i\sqrt{3}$ or x= $1+i\sqrt{3}$ (those are the 2 numbers)

6 0

3 years ago

Need help pls pls pls pls

tia_tia [17]

Answer:

letter D is the correct answer here.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers