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tatyana61 [14]
2 years ago
11

PLSS HELP ME I WILL GIVE BRAINLIEST PLSSS

Mathematics
1 answer:
Firlakuza [10]2 years ago
4 0

Answer: -2

Step-by-step explanation: Perpendicular lines have negative reciprocal slopes. That means the fraction is flipped and multiplied by negative 1.

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Sin(x2 y2 da r , where r is the region in the first quadrant between the circles with center the origin and radii 1 and 5
Rudik [331]
I assume there's a plus sign missing above...

Convert to polar coordinates, using

\begin{cases}x(r,\theta)=r\cos\theta\\y(r,\theta)=r\sin\theta\end{cases}

Then the Jacobian is

\dfrac{\partial(x,y)}{\partial(r,\theta)}=\begin{vmatrix}x_r&y_r\\x_\theta&y_\theta\end{vmatrix}=\begin{vmatrix}\cos\theta&\sin\theta\\r\sin\theta&-r\cos\theta\end{vmatrix}=-r

Then

\mathrm dA=\mathrm dx\,\mathrm dy=|-r|\,\mathrm dr\,\mathrm d\theta=r\,\mathrm dr\,\mathrm d\theta

so the integral can be written as

\displaystyle\iint_R\sin(x^2+y^2)\,\mathrm dA=\int_0^{\pi/2}\int_1^5r\sin(r^2)\,\mathrm dr\,\mathrm d\theta

Let s=r^2, so that \dfrac{\mathrm ds}2=r\,\mathrm dr.

\displaystyle\frac12\int_0^{\pi/2}\int_1^{25}\sin s\,\mathrm ds\,\mathrm d\theta=-\frac12(\cos25-\cos1)\int_0^{\pi/2}\mathrm d\theta=\frac\pi4(\cos1-\cos25)
3 0
3 years ago
Write an equivalent algebraic equation for the sentence below.
tatuchka [14]

Answer:

x-7=13

Step-by-step explanation:

x-7= 13

hope that helps

5 0
3 years ago
Can u please help me with question c
densk [106]

Answer:

see explanation

Step-by-step explanation:

Under a reflection in the y-axis

a point (x, y ) → (- x, y )

Hence

A'(-5, - 3 ) → A''(5, - 3 )

B'(4, 4 ) → B''(- 4, 4 )

C'(4, 2 ) → C''(- 4, 2 )

D'(- 2, - 1 ) → D''(2, - 1 )


8 0
3 years ago
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nikdorinn [45]
Since it starts at 12 and is increasing by 5 each time, the 70th term will be;
12 + 5(70)
12 + 350
362

362 is the 70th term of the sequence.
8 0
3 years ago
Read 2 more answers
PLEASE HELP! I WILL GIVE BRAINLIEST! PLEASE SHOW YOUR WORK TOO :))!!
Juliette [100K]

Answer:>

Step-by-step explanation:

8 0
3 years ago
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