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3 years ago

The numbers of blocked intrusion attempts on each day during the first two weeks of

2 answers:

4 0

(a) Construct a 95% confidence interval for the difference between the average number of intrusion attempts per day before and after the change of firewall setting (assume equal variance)

rodikova [14]3 years ago

4 0

here is your answer hope it's helpful for you thankyou

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So I kinda forgot how to do this *nervous laughter* um help

natali 33 [55]

1) value of x =60

2) value of x = 3

Step-by-step explanation:

We need to use cross products to solve the proportions of x.

$1.\,\, \frac{3}{5}= \frac{x}{100}$

Solving:

$\frac{3}{5}= \frac{x}{100}\\Cross\,\,multiply\,\,:\\5x=3*100\\5x=300\\x=\frac{300}{5}\\x=60$

So, value of x =60

$2.\,\,\frac{x}{8}=\frac{7.5}{20}$

$\frac{x}{8}=\frac{7.5}{20} \\20x=7.5*8\\20x=60\\x=\frac{60}{20}\\ x=3$

So, value of x = 3

Keywords: Ratio and Proportions

Learn more about Ratio and Proportions at:

#learnwithBrainly

7 0

3 years ago

When you divide a whole number by a decimal less than 1, the quotient is greater than the whole number. Why?

Setler [38]

For this type of problem you would have to move the decimal as many places to the right as needed to make the divisor a whole number the you would move the dividend the same amount of times even if it is a whole number . Then you use what you have to divide normally. Hope this helps!

3 0

3 years ago

Suppose we have collected times, in minutes, that it takes volunteers to complete a set of pencil and paper mazes. Volunteers ar

Leto [7]

Answer:

Is an experimental study

Step-by-step explanation:

In an observational study you don't control any aspect of the investigation you just observe the variables that you determined since the beginning without any intervention.

In this case you are controlling who sees one or the other video, then you are controlling one of the variables that is the type of video each group sees and because of this it is an experimental study. Researchers designed an experiment to prove the null hypothesis they had.

3 0

3 years ago

Find a fraction equivalent to 5/7 whose squared terms add up to 1184.

bogdanovich [222]

The system of equations of two unknowns is formulated and solved.

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28 } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ x=\dfrac{5}{7}(\pm 28)=\pm 20 } \end{gathered}$}$

The fraction that satisfies the request is $\bf{\dfrac{20}{28}}$ , since in $\bf{\dfrac{-20}{-28}}$ the negative signs are canceled and the first fraction is obtained.

3 0

2 years ago

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6

faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that [the difference found in part (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0

4 years ago