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3 years ago

If DE is not parallel to BC, what is DE?

Mathematics

1 answer:

stiks02 [169]3 years ago

4 0

They are corresponding angles

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In base 2 (Binary system), which equation is false?

cluponka [151]

Answer:

it is a

Step-by-step explanation:

because 11 +1 8n binary is qlways 100 bbecause 11 is in the 4th in the truth table of binary numbers and 100 is in the 5th so 11 + 1 = 4+1

100 = 5

pls mark it as the brainlyest answer

5 0

2 years ago

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Charlene bought a used.It cost $43.00.A new skateboard costs 3 times as much as the used one Charlene bought.How much does a new

vovangra [49]

Multiply it by 3.
43.00*3=129=priceNewSkateboard

6 0

3 years ago

The school cafeteria seats 250 students. 203 students are already seated. Write and sole an inequality that represents the addit

Nitella [24]

Answer:

An equation that represents the given situation is $203+x=250$ and the additional number of students that can be seated is 47

Step-by-step explanation:

Number of students already seated in school cafeteria = 203

Let x be the additional number of students that can be seated

So, Total number of seats available in school cafeteria = 203+x

We are given that the school cafeteria seats 250 students

So, 203+x=250

$\Rightarrow x=250-203$

$\Rightarrow x=47$

Hence an equation that represents the given situation is $203+x=250$ and the additional number of students that can be seated is 47

6 0

3 years ago

The variables A, B, and C represent polynomials where A=x^2, B=3x+2, and C=x-3. What is AB-C^2 in simplest form?

yuradex [85]

Answer:

AB-C^2 = 3x^3 + x^2 + 9

Step-by-step explanation:

AB = (x^2)*(3x+2)= 3x^3 + 2x^2

C^2= (x-3)^2 = x^2 - 9

AB-C^2 = 3x^3 + 2x^2 - x^2 + 9 = 3x^3 + x^2 + 9

7 0

3 years ago

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Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (

Vladimir79 [104]

Answer:

Factors: $(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

Step-by-step explanation:

We are given a polynomial:

$f(x)=x^4-x^3-2x-4$

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

$f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

8 0

3 years ago