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schepotkina [342]

2 years ago

15

Can someone help me please?

2 answers:

Rainbow [258]2 years ago

7 0

Answer:

the first option is correct

since value of a will be found through division.

son4ous [18]2 years ago

3 0

Answer: Subtraction

Step-by-step explanation:

you need to subtract 22 and move it to the other side to determine the value of A

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emelia went out to eat dinner in the mail cost $20 with emalia received 30% has done what is the total value of the discount?

Viktor [21]

A. Emilia is rich and eats like a pig

7 0

3 years ago

Let y = (2 6) and u = (7 1). Write y as the sum of a vector in Span(u) and a vector orthogonal to .

Minchanka [31]

The question is missing. Here is the complete question.

Let y = $\left[\begin{array}{ccc}2\\6\end{array}\right]$ and u = $\left[\begin{array}{ccc}7\\1\end{array}\right]$ . Write y as the sum of a vector in Span(u) and a vector orthogonal to u.

Answer: y = $\left[\begin{array}{ccc}\frac{21}{10} \\ \frac{3}{10} \end{array}\right] + \left[\begin{array}{ccc}\frac{-1}{10}\\ \frac{57}{10} \end{array}\right]$

Step-by-step explanation: The sum of vectors is given by

y = $y_{1}$ + z

where $y_{1}$ is in Span(u);

vector z is orthogonal to it;

First you have to compute the orthogonal projection $y_{1}$ of y:

$y_{1}$ = proj y = $\frac{y.u}{u.u}.u$

Calculating orthogonal projection:

$\left[\begin{array}{c}2\\6\end{array}\right]$ . $\left[\begin{array}{c}7\\1\end{array}\right]$ = $\left[\begin{array}{c}9\\6\end{array}\right]$

$\left[\begin{array}{c}7\\1\end{array}\right]$ . $\left[\begin{array}{c}7\\1\end{array}\right]$ = $\left[\begin{array}{c}49\\1\end{array}\right]$

$y_{1} = \frac{9+6}{49+1}.u$

$y_{1} = \frac{15}{50}.u$

$y_{1} = \frac{3}{10}.u$

$y_{1} = \frac{3}{10}.\left[\begin{array}{c}7\\1\end{array}\right]$

$y_{1} = \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right]$

Calculating vector z:

z = y - $y_{1}$

z = $\left[\begin{array}{c}2\\6\end{array}\right] - \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right]$

z = $\left[\begin{array}{c}\frac{-1}{10} \\\frac{57}{10} \end{array}\right]$

Writing y as the sum:

$y = \left[\begin{array}{c}\frac{21}{10} \\\frac{3}{10} \end{array}\right] + \left[\begin{array}{c}\frac{-1}{10} \\\frac{57}{10} \end{array}\right]$

5 0

3 years ago

Can someone please solve this using quadratic formula <br><br> 2x^2 -7x -15=0

saw5 [17]

Step-by-step explanation:

a=2

b=-7

c=-15

-(-7)+-sq root (-7)²-4(2)(-15) / 2(2)

7 +- sq root 169 / 4

7+- 13 / 4

7+13 / 4, 7-13 / 4

x=5 x=-3/2

7 0

3 years ago

a bus is traveling at a constant speed . if the the bus travels 15 1/2 miles in 1/3 of an hour , how many miles will the bus tra

Drupady [299]

Answer:

46.5 miles per hour

Step-by-step explanation:

15 1/2 (15.5) miles = 1/3 hour (20 minutes)

15.5 miles x 3 = 46.5 miles per hour

7 0

4 years ago

PLEASE HELP!<br> How much is 1/3 of Rs.30 ? _

Mariulka [41]

Answer:

$\frac{1}{3}\ of\ Rs.30 = Rs.10$

Step-by-step explanation:

Given

$\frac{1}{3}\ of\ Rs.30$

Required

Solve

of means *. So, we have:

$\frac{1}{3}\ of\ Rs.30 = \frac{1}{3}\ *\ Rs.30$

$\frac{1}{3}\ of\ Rs.30 = \frac{1\ *\ Rs.30}{3}$

$\frac{1}{3}\ of\ Rs.30 = \frac{Rs.30}{3}$

$\frac{1}{3}\ of\ Rs.30 = Rs.10$

8 0

3 years ago