Umm what’s the question??

is equal to 2x, since it is the derivative of

.
By the definitions of cosecant, secant, and cotangent, we have

Then we rewrite the fraction as

The reason for this is that we want to apply the well-known limit,

for
. So when we take the limit, we have


Answer:
x = 18
Step-by-step explanation:
We can say that:
(2x + 13) + 90 + 41 = 180
2x + 144 = 180
2x = 36
x = 18
Hope this helps!