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2 years ago

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The length of a rectangle is 5 times its width. Write an expression you would use to find the length when given the width (w). W

hat is the length of the rectangle if its with is 20 inches?

1 answer:

nadya68 [22]2 years ago

4 0

Let 5w equal the length and w equal the width.

5w + w = Area
6w = Area

5(20) = Length
Length = 100 inches

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The limit of this function does not exist.

Step-by-step explanation:

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To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

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Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

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Do 2 divided by fifty eight squared

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The table shows the height of Sonya‘s siblings who is taller Frida or Julia compare their hearts using the simple >

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The height of Julio greater than the height of Frieda .

Step-by-step explanation:

Given height as :

The height of Frieda = 5 $\frac{1}{4}$ ft

The height of Julio = 5 $\frac{5}{6}$ ft

So, The height of Frieda = 5 $\frac{1}{4}$

= 5 + $\frac{1}{4}$

= $\frac{20+1}{4}$

= $\frac{21}{4}$ feet

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And The height of Julio = 5 $\frac{5}{6}$ ft

So, The height of Julio = 5 $\frac{5}{6}$

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= $\frac{30+5}{6}$

= $\frac{35}{6}$ feet

∴ The height of Julio = 5.83 feet

Since 5.83 feet $>$ 5.25 feet

So the height of Julio $>$ the height of Frieda

Hence The height of Julio greater than the height of Frieda . Answer

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Independent random samples are taken at a university to compare the average GPA of seniors to the average GPA of sophomores. Giv

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Correct options is (A).

Step-by-step explanation:

A (1 - <em>α</em>)% confidence interval can be constructed to determine whether there is any difference between the average GPA of seniors and the average GPA of sophomores.

The hypothesis can be defined as:

<em>H₀</em>: There is no difference between the average GPA of seniors and the average GPA of sophomores, i.e. <em>μ</em>₁ - <em>μ</em>₂ = 0.

<em>Hₐ</em>: There is a difference between the average GPA of seniors and the average GPA of sophomores, i.e. <em>μ</em>₁ - <em>μ</em>₂ ≠ 0.

The (1 - <em>α</em>)% confidence interval for the difference between two means is:

$CI=(\bar x_{1}-\bar x_{1})\pm z_{\alpha /2}\times SE$

Decision rule:

If the confidence interval contains the mull value, i.e. 0, then the null hypothesis will be failed to be rejected and vice-versa.

The 95% confidence interval for the difference between the true average GPAs (seniors - sophomores) is (0.53, 1.61).

The 95% confidence interval dos not contains 0. Thus, the null hypothesis will be rejected.

Conclusion:

There is a significant difference between the average GPA of seniors and the average GPA of sophomores.

The 95% confidence interval for the difference between the true average GPAs (0.53, 1.61), implies that there is a 95% confidence that the average GPA of seniors is greater than the average GPA of sophomores.

Thus, the correct options is (A).

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