We know that
Part 1)
[surface area of a cone without base]=<span>π*r*l
r=3 in
l=slant height ----> 6 in
</span>[surface area of a cone without base]=π*3*6------> 56.52 in²
[surface area of a cylinder]=π*r²+2*π*r*h------> only one base
r=3 in
h=5 in
[surface area of a cylinder]=π*r²+2*π*r*h
[surface area of a cylinder]=π*3²+2*π*3*5-----> 122.46 in²
[surface area of the composite figure]=56.52+122.46-----> 178.98 in²
the answer Part A) is
178.98 in²
Part B)
[surface area of the composite figure]
=12*16+2*12*7+2*16*7+5*12+5*16+13*16----> 932 ft²
the answer Part B) is
932 ft²
since the polygon has 8 chambers the angle of one chamber = 360/8 = 45°
so the angle WOP = 45°
now drawing a imaginary line which seperates the triangleWOP into half
so the angle of imaginary line is 45/2 = 22.5
sin(theta) = opp/hyp
since WP (opp) is unknown. take as x
sin(22.5) = x/44
0.383×4 = x
x = 1.532 (app) = 1.5 cm
perimeter = 1.5 × 8
= 12 cm
area of triangle WOP = 2×1/2 ×bh = bh
= 4×1.5
= 6 cm²
so the area of regular polygon = 8× area of a triangle
= 48 cm²
Answer:
55 degrees in Celsius
Step-by-step explanation:
here is a formula to help: (131°F - 32) x 5/9 (the / is not for division, it's a fraction) = 55°C
