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Yuki888 [10]
3 years ago
6

Find the area of this parallelogram

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

Area of parallelogram= base × perpendicular height

base= 20cm height= 13

Area= 20cm×13cm

Area= 260cm²

Therefore the area of the parallelogram is 260cm²

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A line passes through point A(10,15). A second point on the line has an x-value that is 125% of the x-value of point A and a y-v
melisa1 [442]

The equation of the line in the point-slope form is y - 15 = -\frac{3}{2} (x - 10)

Step-by-step explanation:

The point-slope form of a linear equation is y-y_{1}=m(x-x_{1}) , where

  • m is the slope of the line, where m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , (x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line
  • (x_{1},y_{1}) is a point on the line

∵ Point A = (10 , 15)

∵ The x-coordinate of the second point is 125% of x-coordinate

  of point A

∴ x-coordinate of second point = \frac{125}{100} × 10

∴ x-coordinate of second point = 12.5

∵ The y-coordinate of the second point is 75% of y-coordinate

  of point A

∴ y-coordinate of second point = \frac{75}{100} × 15

∴ y-coordinate of second point = 11.25

∴ The coordinates of the second point are (12.5 , 11.25)

Let us find the slope of the line by using the rule of it above

∵ (x_{1},y_{1}) = (10 , 15)

∵ (x_{2},y_{2}) = (12.5 , 11.25)

∴ m=\frac{11.25-15}{12.5-10}=\frac{-3.75}{2.5}=-\frac{3}{2}

Now we can write the equation

∵ The point-slope form is y-y_{1}=m(x-x_{1})

∵ m=-\frac{3}{2}

∵ (x_{1},y_{1}) = (10 , 15)

- Substitute these values in the form of the equation

∴ y - 15 = -\frac{3}{2} (x - 10)

The equation of the line in the point-slope form is y - 15 = -\frac{3}{2} (x - 10)

Learn more:

You can learn more about the linear equation in brainly.com/question/4152194

#LearnwithBrainly

5 0
3 years ago
What do you multiple 24 with to get 120
ohaa [14]

Answer:

5

Step-by-step explanation:

I divided \frac{120}{24} = 5

3 0
3 years ago
Read 2 more answers
PLEASEEEEEE HELPPPP
Ne4ueva [31]
This is just like an exponential growth equation...

Final=initial*rate^periods

25000=12500(1.0525)^t

2=1.0525^t

ln2=t ln1.0525

t=ln2/ln1.0525

t=13.55

t=14 yrs
4 0
3 years ago
Read 2 more answers
Find all solutions in the interval [0,2pi).<br><br> cos 2x + sqrt(2) sinx=1
kykrilka [37]
<span>cos 2x + sqrt(2) sinx=1
</span><span>
Note that: cos 2x = cos^2x - sin^2x = (1-sin^2x) - sin^2x = 1 - 2sin^2x.
So, when alternatively written, you have the following equation:

</span>- 2sin^2x + sqrt(2)sinx + 1 = 1
- 2sin^2x + sqrt(2)sinx = 0

Then, let z=sin(x). So you get,

- 2z^2 + sqrt(2)z = 0
z(- 2z + sqrt(2)) = 0

Either z=0, or - 2z + sqrt(2) = 0 --->  z=sqrt(2)/2.
Then, since z=0 or z=sqrt(2)/2, therefore sin(x)=0, or sin(x)=sqrt(2)/2.

Then, for you remains just to list the angles. (Let me know if this is not fair or if you got questions.)
6 0
3 years ago
Write the following expression without using<br> negative exponents.
solmaris [256]

Option B:

$\frac{9{s^2} }{4 {m^3} {p^6}}

Solution:

Given expression:

$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}

To write this expression without negative exponents:

$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}

Using exponent rule: a^{-b}=\frac{1}{a^b}

$m^{-3}=\frac{1}{m^3}

$p^{-6}=\frac{1}{p^6}

$s^{-2}=\frac{1}{s^2}

Substitute these in the expression.

$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}=\frac{9 \frac{1}{m^3}  \frac{1}{p^6} }{4 \frac{1}{s^2} }

Denominator of fraction in denominator goes to numerator.

Denominator of fraction in numerator goes to denominator.

Therefore, s^2 goes to numerator and m^3p^6 goes to denominator.

               $=\frac{9 \times {s^2}   }{4 {m^3}\times{p^6}}

              $=\frac{9{s^2} }{4 {m^3} {p^6}}

Option B is the correct answer.

$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}=\frac{9{s^2} }{4 {m^3} {p^6}}

7 0
3 years ago
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