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3 years ago

What's 2/3 times 3/11 in simplest form

Mathematics

1 answer:

myrzilka [38]3 years ago

3 0

The answer is 2/11 in simplest form

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Which values of c will cause the quadratic equation -- x2 + 3x + c = 0 to have no real number solutions? Check all that

Novay_Z [31]

Answer:

c=5x

Step-by-step explanation:

:D good luck

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3 years ago

Rewrite the equation 2x + 6y = 7 in slope-intercept form.

4vir4ik [10]

Answer: y = -2x + 1 1/6

Steps:
2x + 6y = 7
2x + y = 7/6
y = 7/6
y = -2x + 7/6
y = -2x + 1 1/6

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3 years ago

Read 2 more answers

Which expression is equivalent to 2x^(2)+11x+5

beks73 [17]

Answer:

(x + 5)(2x + 1)

Step-by-step explanation:

Given

2x² + 11x + 5

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 2 × 5 = + 10 and sum = + 11

The factors are + 10 and + 1

Use these factors to split the x- term

2x² + 10x + x + 5 ( factor the first/second and third/fourth terms )

= 2x(x + 5) + 1 (x + 5) ← factor out (x + 5 from each term

= (x + 5)(2x + 1) ← in factored form

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3 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

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4 years ago

On $500 at 6% for 18 months what is the interest

blsea [12.9K]

It would be $45. The equation is 500×0. 06×1.5

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3 years ago