Question

What is the perimeter? Geometry!!!

Answer 1

Answer:

it's little difficult to solve

Answer 2

Answer:

$2\sqrt{29}+\sqrt{53}+5$

Step-by-step explanation:

The distance between A and B is a vertical distance of $2$ and a horizontal distance of $5$. By the Pythagorean Theorem, $AB=\sqrt{2^2+5^2}=\sqrt{29}$.

The distance between B and C is $5$ by counting squares.

The distance between C and D is a vertical distance of $2$ and a horizontal distance of $7$. By the Pythagorean Theorem, $CD=\sqrt{2^2+7^2}=\sqrt{53}$.

The distance between D and A is a vertical distance of 5 and a horizontal distance of $2$. By the Pythagorean Theorem, $DA=\sqrt{5^2+2^2}=\sqrt{29}$.

So, the answer is $\boxed{2\sqrt{29}+\sqrt{53}+5}$