Question

What is the absolute value of the complex number -4-square root of 2i? Hurrryyy

Answer 1

$|-4-\sqrt{2}i|=\sqrt{(-4)^2+(-\sqrt{2})^2}=\sqrt{16+2}=\sqrt{18}=\sqrt{9\cdot3}=\sqrt{9}\cdot\sqrt{3}=\\\\=\boxed{3\sqrt{2}}$