Question

Find the quotient................................

Answer 1

Answer:

A.  $2a^3+3a^2-5a$

Step-by-step explanation:

we are given

$(4a^4+6a^3-10a^2)$÷(2a)

so, we can divide 2a to all the terms

and we get

$\frac{(4a^4+6a^3-10a^2)}{2a} =\frac{4a^4}{2a}+\frac{6a^3}{2a}-\frac{10a^2}{2a}$

we can simplify it

$\frac{(4a^4+6a^3-10a^2)}{2a} =\frac{2a\times 2a^3}{2a}+\frac{2a\times 3a^2}{2a}-\frac{2a\times 5a}{2a}$

$\frac{(4a^4+6a^3-10a^2)}{2a} =2a^3+3a^2-5a$

so, quotient is

$2a^3+3a^2-5a$

Answer 2

Answer:

A

Step-by-step explanation:

To find this quotient, we divide each term inside the parenthesis by $2a$. Then we simplify. So we have:

$\frac{4a^4}{2a}+\frac{6a^3}{2a}-\frac{10a^2}{2a}\\=2a^{4-1}+3a^{3-1}-5a^{2-1}\\=2a^3+3a^2-5a$

Answer choice A is correct.