Answer:
When Sum of square of two Sides is equal to square of third side of triangle.
Step-by-step explanation:
Given:
Three side length of triangle are given we need find the which value to substitute for a, b, c in Pythagoras theorem.
First we will find the squares of all length, then we will check which two square of side are equal to square of third side as per Pythagoras theorem.
Hence the two side would according be a and b and third side will become c.
For example if length of triangle is given as 6 cm, 8 cm and 10 cm.
We will first take square of all
Now we can see that
Now by Pythagoras theorem.
Hence we can say a = 6 cm, b = 8 cm, c= 10 cm
Step-by-step explanation:
The required sum
=(1+2+3+...+199)−(3+6+9+...+198)−(5+10+15+...+195)+(15+30+45+...+195)
=2199(1+199)−266(3+198)−239(5+195)+213(15+195)
=199×100−33×201−39×100+13×105=10732
We have been given a diagram and we need to find the value of arc angle a.
According to one of the circle theorems the angle at the centre of a circle is twice the angle at the circumference subtended by the same arc.
Therefore, arc angle a will be twice of the angle at circumference, that is, 34 degrees.
Therefore, value of angle a is:
3 squares = 4 circles, so (number of squares)/(number of circles) = 3/4.
3/4 = 12/16
:::::
4 squares = 2 circles, so (number of squares)/(number of circles) = 4/2.
4/2 = 2/1
:::::
2 squares = 5 circles, so (number of squares)/(number of circles) = 2/5.
2/5 = 4/10
