Answer:
3rd quadrant
Step-by-step explanation:
- First we just convert the angle from radians to degrees
- Now that's too big, all this means is if we start rotating from the positive y-axis in a circle we will cross the starting point 2 times, 2 full circles;
- Now in which quadrant it 210 degrees?
- 0 degrees to 90 degrees is 1st quadrant
- 90 degrees to 180 degrees is 2nd quadrant
- 180 degrees to 270 degrees is 3rd quadrant
- 270 degrees to 360 degrees is 4th quadrant
- So our answer is the 3rd quadrant.
Answer:
is a polynomial of type binomial and has a degree 6.
Step-by-step explanation:
Given the polynomial expression

Group like terms

Add similar elements: -8c-8c-9c=-25c

Thus, the polynomial is in two variables and contains two, unlike terms. Therefore, it is a 'binomial' with two, unlike terms.
Each term has a degree equal to the sum of the exponents on the variables.
The degree of the polynomial is the greatest of those.
25c has a degree 1
has a degree 6. (adding the exponents of two variables 'c' and 'd').
Thus,
is a polynomial of type binomial and has a degree 6.
Answer:
y=1/2x-1
Step-by-step explanation:
-4y=4-2x
4y=4-2x
y=-1+1/2x
y=1/2x-1
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Answer: XWY and STR</h3>
I tend to think of parallel lines as train tracks (the metal rail part anyway). Inside the train tracks is the interior region, while outside the train tracks is the exterior region. Alternate exterior angles are found here. Specifically they are angles that are on opposite or alternate sides of the transversal cut.
Both pairs of alternate exterior angles are shown in the diagram below. They are color coded to help show how they pair up and which are congruent.
A thing to notice: choices B, C, and D all have point W as the vertex of the angles. This means that the angles somehow touch or are adjacent in some way due to this shared vertex point. However, alternate exterior angles never touch because parallel lines never do so either. We can rule out choices B,C,D from this reasoning alone. We cannot have both alternate exterior angles on the same exterior side of the train tracks. Both sides must be accounted for.
Rotation of triangle JKL by 180 degrees will result in a triangle with corresponding vertices of (2, 4), (3, 2) and (-1, 2).
Then translating the resulting triangle 2 units up will result in a triangle with corresponding vertices (4, -2), (2, -3) and (2, 1) which is the same triangle as the given triangle MNP.
Therefore, the statement that best explains whether △JKL is congruent to △MNP is △JKL is congruent to △MNP because △JKL can be mapped to △MNP by a
rotation of 180° about the origin followed by a translation 2 units up.