Please solve -7x > -2(x+15) < 10

Mathematics

2 answers:

likoan [24]2 years ago

5 0

Answer:

${ \rm{ - 7x > - 2(x + 15) < 10}} \\ \\ { \tt{ - 7x > ( - 2x - 30) < 10}} \\ \\ { \tt{ ( - 7x + 30) > - 2x 2x < - 40}} \\ \\ { \boxed{ \tt{(3.5x - 15) > x < - 20}}}$

Scilla [17]2 years ago

4 0

Answer:

-20<x<6

Step-by-step explanation:

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Which equation represents the value of x? x=100−y2−−−−−−−√ x=10+y2 x=10−y x=y2+100−−−−−−−√ Right triangle A B C with angle B as

Nostrana [21]

Answer:

Therefore the required value of x,

$x=\sqrt{(100-y^{2})}$

Step-by-step explanation:

Given:

ΔBC is a Right Angle Triangle at ∠ B = 90°

As ∠ B = 90° , AC will be the Hypotenuse

AC = 10 = Hypotenuse

BC = y = Longer leg ( say )

AB = x = Shorter leg ( say )

To Find :

x = ?

Solution:

In Right Angle Triangle Δ ABC , By Pythagoras Theorem we get

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Substituting the given values we get

$10^{2}= x^{2}+y^{2} \\\\x^{2}=100-y^{2} \\\\\textrm{square rooting on both the side we get}\\\\x=\sqrt{(100-y^{2})}\\\therefore x=\sqrt{(100-y^{2})}\ \textrm{ which is the required value of x}$