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nata0808 [166]
3 years ago
8

Please solve -7x > -2(x+15) < 10​

Mathematics
2 answers:
likoan [24]3 years ago
5 0

Answer:

{ \rm{ - 7x >  - 2(x + 15) < 10}} \\  \\ { \tt{  - 7x > ( - 2x - 30) < 10}} \\  \\ { \tt{ ( - 7x  + 30) >  - 2x  2x <  - 40}} \\  \\ { \boxed{ \tt{(3.5x - 15) > x <  - 20}}}

Scilla [17]3 years ago
4 0

Answer:

-20<x<6

Step-by-step explanation:

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Answer:

3x + ( - 2 - 3) = 19 \\ 3x+(- 5) = 10 + 9 \\ (1 + 2)x + ( - 5) = 19

all values stand for 3x+(-5)=19

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2 years ago
Please answer this correctly
MrMuchimi

Answer:

11 pt

Step-by-step explanation:

There are 2 pints in one quart. This means that there are 10 pints in 5 quarts, plus 1 would be 11.

3 0
2 years ago
You know of a relative who is addicted to pain killers. Due to his history, 2.3g of Tylenol per day is dangerous. He takes 200 m
Nezavi [6.7K]

Answer: So, your relative takes N tablets each 6 hours. a day has 24 hours, and 24/6 = 4, so he takes N tablets 4 times per day, so he takes 4*N tablets.

each tablet has 200mg, and 2.3 g (or 2300 mg) is toxic.

this means that 4*N*200mg must be less than 2300, if we are seeking for the maximum N possible, then:

4*N*200mg = 2300mg

4*N = 2300/200 = 11.5

N = 11.5/4 = 2.87

if you round up this number, you will end up taking more than 2.3g of tylenol per day, this implies that N must be equal to 2.

So your relative needs to take maximum 2 tablets per day.

7 0
3 years ago
Which of the following functions is graphed below?
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Step-by-step explanation:-

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8 0
3 years ago
$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102  

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

I_1 -  I_2 = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

8 0
3 years ago
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