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3 years ago

Please help me with this

Mathematics

1 answer:

o-na [289]3 years ago

4 0

Answer:

$\frac{2}{3}$

Step-by-step explanation:

If we use the form y=kx where k is the constant of proportionality we can see that $k=\frac{2}{3}$ in this instance is our constant of proportionality because $\frac{2}{3}$ is the constant number we multiply x by.

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What is x3/4 equivalent to

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Is that the whole question

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3 years ago

What fractions are equivalent to 9/18

sergey [27]

Equivalent fractions are fractions that can be simplified down to the same thing.

For example, 9/18 can be simplified down to 1/2

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The difference of two numbers is 8. If the sum of the smaller number and the square of the larger

galben [10]

Answer:

Step-by-step explanation:

12^2 is the greatest number that is closest to 148. then there is 4 as the smaller number 12-4=8

144+4=148

6 0

3 years ago

If a coin is tossed three times, find probability of getting

Assoli18 [71]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

1) Exactly 3 tails 

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: tails)} = \red{ \dfrac{1}{8}}$

2) At most 2 heads

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

$\therefore \sf Probability_{(at \: most \: 2 \: heads)} = \green{ \dfrac{7}{8}}$

3) At least 2 tails 

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

4) Exactly 2 heads 

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

5) Exactly 3 heads

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

8 0

2 years ago

8 multiplied by 3/4 divided by 3/3

bezimeni [28]

8 * 3/4

Multiply 8 by 4 to get 32 then divide 32 by 3 to get 3.6 repeating

3/3 is basically 1 so its still 3.6

3.6 is 3 3/5

-XCalypso

~ Dont forget to rate, thank and vote brainliest answer! :D ~

5 0

3 years ago