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katrin2010 [14]
2 years ago
9

Quick Question: did I do this right?

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
4 0

Answer:

tske the L to have with me or 1v1 me first to 2

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The variable $x$ varies directly as the square of $y$, and $y$ varies directly as the cube of $z$. If $x$ equals $-16$ when $z$
Kisachek [45]

If x varies directly as y^2, then there is some constant a for which

x=ay^2

Similarly, there is some constant b such that

y=bz^3

Given that x=-16 when z=2, we have

\begin{cases}-16=ay^2\\y=8b\end{cases}\implies-16=a(8b)^2\implies ab^2=-\dfrac14

Now when z=\frac12, we get

\begin{cases}x=ay^2\\y=\frac b8\end{cases}\implies x=a\left(\dfrac b8\right)^2=\dfrac{ab^2}{64}=\dfrac{-\frac14}{64}=\boxed{-\dfrac1{256}}

6 0
4 years ago
Simplify:
miv72 [106K]

576 =  {2}^{6}  \times  {3}^{2}  \\  \\
64 =  {2}^{6}






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6 0
3 years ago
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4 0
3 years ago
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The graph shows f(x) = 1/2 and its translation, g(x).
AnnyKZ [126]
As you can see, each point on f(x) is moved up 4 units to get to g(x), so the function is g(x) = f(x) + 4.  The f(x) function cannot possibly be f(x)=1/2, though, because that would be a horizontal line through y = 1/2 and that function is clearly not a horizontal line.  So whatever f(x) is REALLY, add 4 to the tail end of it to show its translation.
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Convert 59 degrees F to Celsius, using the formula C = 5 (F - 32).
telo118 [61]
C = 5(59-32)
C = 5(27)
C = 135
5 0
3 years ago
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