Answer:

Step-by-step explanation:
Answer:
b/h
Step-by-step explanation:
remember SOH CAH TOA. Sin = opposite/hypotenuse, cos = adjacent/hypotenuse, tan = opposite/adjacent. So in this case use CAH for cos L. Adjacent to L is b, and the hypotenuse is h. Therefore the answer is b/h.
<span>15<span>(<span>6−g</span>)</span></span><span>=<span><span>(15)</span><span>(<span>6+<span>−g</span></span>)</span></span></span><span>=<span><span><span>(15)</span><span>(6)</span></span>+<span><span>(15)</span><span>(<span>−g</span>)</span></span></span></span><span>=<span>90−<span>15g</span></span></span><span>=<span><span>−<span>15g</span></span>+<span>90</span></span></span>
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required lengths are not given.
I will use the following data set to answer the question.

First, is to determine the range of the dataset



Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval




<em>So, we use 4 classes</em>
Plot the frequency distribution table as follows:

<em>See attachment for histogram</em>