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▹ Answer
<em>1/3a + c - 7b</em>
▹ Step-by-Step Explanation
(4/3a - 3c - 5b) + (-a - 2b + 4c)
<u>Remove the parentheses</u>
(4/3a - 3c - 5b) + (-a - 2b + 4c)
<u>Rewrite</u>
4/3a - 3c - 5b - a - 2b + 4c
<u>Calculate</u>
1/3a - 3c - 5b - 2b + 4c
<u>Final Answer</u>
1/3a + c - 7b
Hope this helps!
- CloutAnswers ❁
Brainliest is greatly appreciated!
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Answer:
The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Step-by-step explanation:
Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.
If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.
Compute the value of P (X < 325) as follows:

Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
E = 352.50 euro × 1 pound / 1.41 euro = 250.00 pounds
J = 39856 yen × 1 pound / 188 yen = 212.00 pounds
a) Japan is cheaper
b) 250 - 212 = 38 pounds cheaper