Two factors of x²-12x+36 are
(x-6) and (x-6)
Solution;
x²-12x +36
x²-6x -6x +36 ( split -12x in two parts such that if add them we will get-12x and if multiply will get 36x²)
Taking x common from first two terms and 6 from next two terms
x(x-6) -6(x -6)
taking (x-6) common
(x-6)(x-6)
Answer:
where is the question?
Step-by-step explanation:
1) 12
2) -4
I hope this was correct？
Answer:
I think that Nick is correct because you are going to have to make your answer positive and when you do the two fractions -4/9 + -6/9 are going to be 6/9 + 4/9 and there is already a addition sign in the last problem we are just going to keep it there. And when we add we get 10/9 or 1 1/9
If i get it wrong please don't hate im just in 7 grade ok :(
Answer: The hypotenuse is 53 (approximately)
Step-by-step explanation: In this question we shall apply the Pythagoras theorem which states that;
AC^2 = AB^2 + BC^2
Where AC is the hypotenuse and AB and BC are the two other sides. Having been given that the two other sides are 36 and 39 units respectively, the hypotenuse is now,
AC^2 = 36^2 + 39^2
AC^2 = 1296 + 1521
AC^2 = 2817
Add the square root sign to both sides of the equation
AC = 53.0754
Therefore the hypotenuse is approximately 53 units.
