Deon throws a ball into the air. The height h of the ball, in meters, at time t seconds is modeled by the function
1 answer:
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Answer:
A.
Step-by-step explanation:
We have that, ΔABC is transformed to get ΔA''B''C''.
We see that the following transformations are applied:
1. Reflection across x-axis i.e. flipped across x-axis.
Now, ΔABC is reflected across x-axis along the line AC to get ΔA'B'C'.
2. Translated 2 units down i.e. shifted 2 units down and and then translated 6 units to the left i.e. shifted 6 units to the left.
So, ΔA'B'C' is translated 2 units downwards and 6 units to the left to get ΔA''B''C''.
Hence, the sequence of transformations is Reflection across x-axis and then Translation of 2 units down and 6 units left.
Answer:
a = 64
Step-by-step explanation:
The geometric mean of 2 numbers a and b is , then
= 16
( square both sides )
28a = (16 )² = 1792 ( divide both sides by 28 )
a = 64
I believe it's ![\sqrt[12]{2}](https://tex.z-dn.net/?f=%20%5Csqrt%5B12%5D%7B2%7D%20)
Hope I helped! ( Smiles )
Hope I helped! ( Smiles )
Answer:
Before we graph we know that the slope, mx, could be read as
. To graph the the equation of the line, we begin at the point (0,0). From that point, because our rise is negative (-1), instead of moving upwards or vertically, we will move downards. Therefore, from point 0, we will vertically move downwards one time. Now, our point is on point -1 on the y-axis. Now, we have 2 as our run. From point -1, we move to the right two times. We land on point (2,-1). Because we need various points to graph this equation, we must continue on. In the end, the graph will look like the first graph given.
For the equation y = 2, the line will be plainly horizontal. Why? Because x has no value in the equation. The variable does not exist in this linear equation. Therefore, it will look like the second graph below. We graph this by plotting the point, (0,2), on the y-axis.
