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3 years ago

10. Trudy bought some shirts for school for $18 each. She also bought 2 pairs of jeans

Mathematics

1 answer:

Rus_ich [418]3 years ago

7 0

Answer:

Hii okay so the answer would be, 8

Step-by-step explanation:

So she spent $200 and got 2 pairs of jeans that costed $50 for both.

So we subtract 50 from 200 which would be 150. This is the total she has

left to spend on her shirts. So 150 divided by 18 (Remember each shirt cost $18) Would be 8.3, we round to the nearest number and it would be 8. Hope this helps!

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The graph highlights two other points on the trend line. Use them to find another equation for the trend line shown for this sca

frutty [35]

Option A:

The equation for the trend line is y = 82x + 998.

Solution:

The points on the line are (2, 1162) and (11, 1900).

Here, $x_1=2, y_1=1162, x_2 = 11, y_2=1900$

Slope of the line:

$$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$$m=\frac{1900-1162}{11-2}$

$$m=\frac{738}{9}$

m = 82

Point-slope formula:

$y-y_{1}=m\left(x-x_{1}\right)$

$y-1162=82\left(x-2\right)$

$y-1162=82x-164$

Add 1162 on both sides of the equation.

$y=82x+998$

The equation for the trend line is y = 82x + 998.

Hence Option A is the correct answer.

4 0

3 years ago

Explain what is meant by the equation lim x → 8 f(x) = 9. If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|. The valu

loris [4]

Complete Question

1 Explain what is meant by the equation lim x → 8 f(x) = 9.

A If |x1 − 8| < |x2 − 8|, then |f(x1) − 9| < |f(x2) − 9|.

B The values of f(x) can be made as close to 8 as we like by taking x sufficiently close to 9.

C f(x) = 9 for all values of x.

D If |x1 − 8| < |x2 − 8|, then |f(x1) − 9|≤ |f(x2) − 9|.

E The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 8.

2 Is it possible for this statement to be true and yet f(8) = 6? Explain.

A Yes, the graph could have a hole at (8, 9) and be defined such that f(8) =6.

B Yes, the graph could have a vertical asymptote at x = 8 and be defined such that f(8) = 6.

C No, if f(8) = 6, then lim x→8 f(x) = 6.

D No, if lim x→8 f(x) = 9, then f(8) = 9.

Answer:

The correct option is D

The correct option is A

Step-by-step explanation:

Generally a a limit function $\lim_{n \to x } f(x) = L$

Tell us that as n tends toward x the values of f(x) tends towards L hence for the first question E is the correct option

Now looking at the second question

Yes it is possible for lim x → 8 f(x) = 9. to be true and f(8) = 6 this is because the graph defined by this limit equation can have a hole the point

(8, 9) and created in such a way that f(8) = 6

7 0

3 years ago

Please help me find DOMAIN/RANGE and the EQATION

mrs_skeptik [129]

Answer:

Domain of the function → (-6, ∞)

Range of the function → (-∞, ∞)

Step-by-step explanation:

Domain of a function is the set of x-values of the function.

Similarly, Range of the function is the set of y-values.

From the graph attached,

Domain of the function → (-6, ∞)

x-values of the function starts from x = -6 (excluding x = -5) and tends to the positive infinity.

Range of the function → (-∞, ∞)

y-values starts from negative infinity and tends to positive infinity.

7 0

3 years ago

The sum of the lengths of two opposite sides of the circumscribed quadrilateral is 12 cm, the length of a radius of the circle i

nasty-shy [4]

Answer:

60cm^2

Step-by-step explanation:

We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...

K = sr

where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.

K = (12 cm) (5cm) = 60 cm²

_____

A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.

8 0

3 years ago

Rewire the rational exponent as a radical

Mice21 [21]

Answer:

$\large\boxed{\sqrt[3]{\left(\dfrac{15}{4}\right)^2}}$

Step-by-step explanation:

$a^\frac{n}{m}=\sqrt[m]{a^n}\\---------------------\\\\\left(5\times\dfrac{3}{4}\right)^\frac{2}{3}=\left(\dfrac{5\times3}{4}\right)^\frac{2}{3}=\left(\dfrac{15}{4}\right)^\frac{2}{3}=\sqrt[3]{\left(\dfrac{15}{4}\right)^2}$

Answer:

$\large\boxed{C.\ \sqrt5}$

Step-by-step explanation:

$\left(5^\frac{3}{4}\right)^\frac{2}{3}\\\\\text{Use}\ (a^n)^m=a^{nm}\\\\5^{\frac{3}{4}\cdot\frac{2}{3}}=5^{\frac{1}{2}\cdot\frac{1}{1}}=5^\frac{1}{2}=\sqrt[2]5=\sqrt5$

5 0

3 years ago