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NikAS [45]
3 years ago
9

How to make an equation for unit rate

Mathematics
1 answer:
cricket20 [7]3 years ago
6 0
Rate= distance / time
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Evaluate the difference quotient for the given function. Simplify your answer.
hammer [34]

Answer:

  -2-h

Step-by-step explanation:

It doesn't hurt to follow directions.

  q=\dfrac{f(3+h)-f(3)}{h}=\dfrac{(5 +4(3+h)-(3+h)^2)-(5 +4(3)-(3)^2)}{h}\\\\=\dfrac{5-5+4(3+h-3)-((3+h)^2-3^2)}{h}=\dfrac{4h-(6h+h^2)}{h}\\\\=\dfrac{-2h-h^2}{h}=\boxed{-2-h}

__

Steps: substitute 3+h and 3 for x in the definition of f(x) and simplify the result.

5 0
3 years ago
Find the x-intercept of the function: f(x) = 6x - 2. Round answer to the nearest hundredth, if necessary. A) (0.39, 0) B) (1.00,
lions [1.4K]
The function f(x) = 6^(x)-2 has an x-intercept at approximately <span>(0.39, 0)
              f(x) =  0 = 6^(x) - 2
                        2  = 6^(x)
       log(2)/log(6)= x
                          x = 0.3868 = 0.39</span>
The answer to this question is A) (0.39, 0).
6 0
3 years ago
Find the value of x will give you five stars pls answer ASAP
maw [93]

Answer:

A - x=13

Step-by-step explanation:

Pythagorean theorem

base is 5 (10/2)

height is 12

5^2 + 12^2 = c^2

25 + 144 = 169

c = 13

8 0
3 years ago
The diagram below shows the dimensions of a triangular park built in a new housing development. Two side lengths and one angle m
evablogger [386]
ANSWER

x = 50.5 \degree

EXPLANATION

We use the sine rule for solving triangles.

This is given by the formula,


\frac{ \sin(A) }{a}  =  \frac{ \sin(B) }{b}  = \frac{ \sin(C) }{c}


From the triangle,

\frac{ \sin(x) }{60}  =  \frac{ \sin(40) }{50}

We multiply both sides of the equation by 60 to get,

sin(x)  =  \frac{ 60\sin(40 \degree) }{50}


sin(x)  = 0.7713



We solve for x to obtain,

x = arcsin(0.7713)


x = 50.475

To the nearest tenth, we round to one decimal place to get,

x = 50.5 \degree

7 0
4 years ago
In parallelogram ABCD, AD = 12 in, m∠C = 46º, m∠DBA = 72º. Find the area of ABCD
dmitriy555 [2]

Answer:

The area of   parallelogram ABCD  is78.42 \mathrm{in}^{2}

Explanation:

Given:

AD = 12 in

m \angle C=46^{\circ}

m \angle D B A=72^{\circ}

To Find:

The area of   parallelogram ABCD=?  

Solution:

When we construct the parallelogram with the given data, we get a parallelogram formed by 12 cm as one side and an angle with 46 degrees.  

The area of the parallelogram can be calculated by a b * \sin (a n g l e)

Substituting the value of a=12  we have

\text { Area of parallelogram }=12 * \text { bsin } 46

<u>To find  the value of b, </u>

We know that area of a triangle can be expressed as,

\text { Area of triangle }=(A b / 2) \sin (\text {angle})

So,

(12 * B D / 2) * \sin 46=(A B * B D / 2) * \sin 72

Cancelling BD and 2 on both sides we get,  

12 * \sin 46=A B * \sin 72

A B=12 * \frac{\sin 46}{\sin 72}

Therefore,

b=\frac{12 \sin 46}{\sin 72}

Substituting the value of b,

=12 *\left(\frac{12 \sin 46}{\sin 72}\right) * \sin 46

=78.42  

So the area of the parallelogram is78.42 \mathrm{in}^{2}

6 0
4 years ago
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