Here how i found my answer.
First, convert the equation to the standard equation of a parabola.
-1/4(y+4)=(x-3)^2 ---multiply -4 on both sides
y+4=-4(x-3)^2 ---subtract 4 on both sides
y=-4(x-3)^2-4
From the equation, we know that the parabola was moved by 3 to the right, because of (x-3)^2. So the axis of symmetry is x=3. Now look at the number in front of (x-3)^2. It is -4. Since it is negative, the parabola opens downwards.
<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
