The park formed like a rectangle so :
Area = length × width
Area = ( 9/10 ) × ( 4/5 )
Area = 9 × 4 / 10 × 5
Area = 9 × 2 × 2 / 5 × 5 × 2
Area = 18 / 25
Answer:
The x-intercept would be 9 and the y-intercept would be -18/5
Step-by-step explanation:
In order to find this we need to first find the slope. To do that we use the two points and the slope equation.
m (slope) = (y2 - y1)/(x2 - x1)
m = (-2 - -6)/(4 - -6)
m = 4/10
m = 2/5
Now that we have the slope, we can use that and either point to find the equation of the line in standard form.
y - y1 = m(x - x1)
y + 6 = 2/5(x + 6)
y + 6 = 2/5x + 12/5
-2/5x + y + 6 = 12/5
-2/5x + y = -18/5
-2x + 5y = -18
Now that we have this, we can find the intercepts through using 0s. First, we put a zero in for y to find the x intercept.
-2x + 5y = -18
-2x + 5(0) = -18
-2x = -18
x = 9
Therefore the x intercept is 9.
We find the y-intercept by doing the opposite. We put a 0 in for x.
-2x + 5y = -18
-2(0) + 5y = -18
5y = -18
y = -18/5
Answer:
y= -3x + 8
Step-by-step explanation:
Put -2x + 6y = -4 into slope-interceltp form
Take the negative reciprocal of the slope.
Use this reciprocal in point-slope form
and you have,
= y= -3x + 8
<em>(EDITED)</em> Steps:
2x+6y = -4
6y=2x - 4
y= 1/3x + 2/3
if two lines are perpendicular,
m1 * m2 + -1
1/3 * m2 = -1
m2 = -3
the line perpendicular to this line is
y = -3x + k ; k ∈ R
the line passes through the point (5,-7)
so,
-7 = -3. (5) +k
-7 = -15 + k
k = 8
∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is
y= -3x + 8
Hope this helps, have a nice day/night! :D
Step-by-step explanation:
m arc AD = (2×108) - 142 = 216-142= 74°
m<A = 180-108= 72°
Answer:
5.5
Step-by-step explanation:
in a rectangle, opp. sides are equal,
∴, KM=LN
∴, 6x+16=49
6x = 33
x = 5.5