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2 years ago

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Please help I don't undestand

1 answer:

Alla [95]2 years ago

3 0

By applying the law of sines and some algebraic handling, the length of the side LJ is approximately equal to 3.517 units. (Right choice: D)

<h3>What is the missing side of the triangle according to the law of sines?</h3>

The law of sines presents a relationship between sides and <em>opposite</em> angles, which is described below:

9/sin 89° = LJ/sin 23° (1)

LJ = 9 × sin 23°/sin 89°

LJ ≈ 3.517

By applying the law of sines and some algebraic handling, the length of the side LJ is approximately equal to 3.517 units. (Right choice: D)

To learn more on law of sines: brainly.com/question/21634338

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What is 5/10 in decimal form?

Snezhnost [94]

.5 or .50 is the answer

8 0

3 years ago

Read 2 more answers

A student has passed 70 percent of the 20 quizzes he has written so far successfully. If this student takes 60 quizzes during th

Ne4ueva [31]

I think the answer is52.4

4 0

3 years ago

Do both of them for 50 points

erastovalidia [21]

Answer:

1) 5.44, 2) 3.9

Step-by-step explanation:

1) a/b + 2b - a^2 when a = 1.4 and b = 0.2

plug in the values:

1.4/0.2 + 2(0.2) - (1.4)^2 = 7 + 0.4 - 1.96 = 5.44

2) a[b-2c]^3 - d/e when a = 2, b = -0.75, c = -1, d = 0, e = -12 5/7 (rewritten to -89/7 = 12.71)

again, plug in the values:

2[-0.75-2(-1)]^3 - 0/12.71 = 2[1.25]^3 - 0 = 2[1.95] = 3.9

5 0

3 years ago

Figure f is a scaled copy of Figure e.

Mekhanik [1.2K]

The correct equation of the scaled figure is given by 6/3 = 4/a

<h3>Scaling</h3>

Scaling is the process of either increasing or decreasing the size of a figure by a factor.

From the diagram attached, Figure f is a scaled copy of Figure e. Figure e is decreased to produce figure f, hence:

AB/XY = CD / WZ
6/4 = 3 / a
6/3 = 4/a

The correct equation of the scaled figure is given by 6/3 = 4/a

Find out more on scaling at: brainly.com/question/10253650

4 0

2 years ago

Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0

3 years ago