The coordinates of point J are(-7,2) , and the midpoint of JK is at L(3,5). What are the coordinates of point K?
2 answers:
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Steps?
A graph shows zeros to be ±3. Factoring those out leaves the quadratic
(x-2)² +1
which has complex roots 2±i.
The function has roots -3, 3, 2-i, 2+i.
A graph shows zeros to be ±3. Factoring those out leaves the quadratic
(x-2)² +1
which has complex roots 2±i.
The function has roots -3, 3, 2-i, 2+i.
First, we are going to rewrite it as a parabola equation.
Rewrite.
Divide by 8.
Factor out coefficient.
Then, we are going to convert x into square form.
Convert the whole expression into square form.
Simplify.
Subtract 6 from both sides.
Divide by coefficient.
Rewrite in standard form.
The radius of the circle will be -2. Also, no matter what the sign says, the radius has to always be positive.
Have a nice day! :)
Rewrite.
Divide by 8.
Factor out coefficient.
Then, we are going to convert x into square form.
Convert the whole expression into square form.
Simplify.
Subtract 6 from both sides.
Divide by coefficient.
Rewrite in standard form.
The radius of the circle will be -2. Also, no matter what the sign says, the radius has to always be positive.
Have a nice day! :)