We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
53
Step-by-step explanation:
5+3=8, 53 flipped is 35, and 53-35=18
Answer:
21+12i i hope this will help you
Step-by-step explanation:
(3-4i)(1+5i)-(2-i)
=[3(1+5i)-4i(1+5i)]-(2-i)
=[3+15i-4i-20i²]-(2-i)
=(3+11i-20i²)-(2-i)
opening brackeys
=3+11i-20i²-2+i
=3+11i+1i-20i²-2
as we know that i²=-1
=3-20(-1)-2+12i
=3+20-2+12i
=21+12i
Step-by-step explanation:
Hope this is correct and helpful
HAVE A GOOD DAY!
Answer:
6 dollars
Step-by-step explanation:
if i am wrong tell me pls
