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krok68 [10]
3 years ago
12

Somebody please help me

Mathematics
1 answer:
Damm [24]3 years ago
5 0

Answer:

3750

Step-by-step explanation:

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How would you solve x^3=8
kozerog [31]

Answer:

2

Step-by-step explanation:

x^{3} =8\\x=\sqrt[3]{8} \\x=2

use your calculator

8 0
3 years ago
Please help will mark you brainiest
Rudik [331]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
A 450m long field is drawn to a scale 1cm to 90cm.find the lenth of drawing<br><br>​
olya-2409 [2.1K]

Answer:

5 cm

Step-by-step explanation:

The length of the drawing will be 450 / 90 = 5 cm.

6 0
3 years ago
Elaina Kicks A Soccer Ball With An Initial Velocity Of
VladimirAG [237]

By using the motion equations, we conclude that she will make the goal.

<h3>Will she make the goal?</h3>

First, we know that the goal is 20ft away, and the position in x is given by:

x = 28*cos(58)*t

Let's find the time in which the ball will travel these 20 ft.

20 =  28*cos(58)*t

(20)/(28*cos(58)) = t = 1.35

So the horizontal distance is covered in 1.35 seconds, now let's see which is the height of the ball at that time.

The height equation is:

y = -16*t^2 +28*sin(58)*t

Evaluating in t = 1.35 we get:

y = -16*(1.35)^2 +28*sin(58)*1.35\\\\y = 2.9

And the goal is 5ft tall, so we can conclude that she will make the goal.

If you want to learn more about motion equations:

brainly.com/question/19365526

#SPJ1

5 0
2 years ago
Find the number that belongs in the green box.<br><br>Round your answer to the nearest tenth​
Umnica [9.8K]

Answer:

134.5 degree

Step-by-step explanation:

first find the remaining side of a triangle

BY using cosine rule

C^2=A^2+B^2-2ABcosx

apply square root both sides

√c^2 =√[4^2+10^2-2(4)(10)cos29]

C=√(116-69.96958)

C=√46.03

C=6.8

Now find angle using cosine rule

C^2=A^2+B^2-2ABcosx

10^2=4^2+6.78^2-2(4)(6.78)cosx

100=16+45.9684-54.24cosx

100=61.9684-54.24cosx

100-61.9684=-54.24cosx

(38.0316)/-54.24=(-54.4cosx)/-54.24

-0.70117=cosx

X= cos inverse of -0.70117

x=134.5 degree

5 0
3 years ago
Read 2 more answers
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