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4 years ago

The cost for any regular priced treat, t, in the store ranges between $1.25 and $5.99.

Mathematics

2 answers:

agasfer [191]4 years ago

7 0

i dont understand what ur question is

netineya [11]4 years ago

5 0

Answer:

Please provide more information on your question for me to fully understand your question?!

Thank you, have a blessed day!!

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Find the measure of the indicated angle to the nearest degree.

Alex_Xolod [135]

Answer: 1. 77.31961650818018 2. 16.26020470831196 3. 75.7499673021964 4. 31.89079180184571 5. 67.38013505195958 6. 28.072486935852954

Step-by-step explanation:

I used a right triangle calculator!

6 0

4 years ago

Evaluate w (-9). w (n) = n2 +5

Artyom0805 [142]

Answer:

w(-9) = 86

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

w(n) = n² + 6

w(-9) is n = -9

Step 2: Evaluate

Substitute: w(-9) = (-9)² + 5
Exponents: w(-9) = 81 + 5
Add: w(-9) = 86

5 0

3 years ago

What type of transformation is shown?

Ilya [14]

I believe it is a reflection?

6 0

3 years ago

Read 2 more answers

kkurt [141]

Answer:

Step-by-step explanation:

1/15 *3=0.2

1/5=0.2

1 ÷5=0.2

7 0

3 years ago

Please Help!!!

algol [13]

$f\left(\dfrac\beta2\right)=\sin\dfrac\beta2$

Recall the half-angle identity:

$\sin^2\dfrac\beta2=\dfrac{1-\cos\beta}2\implies\sin\dfrac\beta2=\pm\sqrt{\dfrac{1-\cos\beta}2}$

So in order to find $f\left(\dfrac\beta2\right)$ , we only need to know the value of $\cos\beta$ . But there are two possible values. To decide which to take, we use the given information: we know that $\beta$ lies in quadrant III, which means $\pi$ , so $\dfrac\pi2$ , which places $\dfrac\beta2$ in quadrant II. In this quadrant, the sine of angle is positive, and so

$\sin\dfrac\beta2=\sqrt{\dfrac{1-\cos\beta}2}$

$\beta$ is an angle of a ray whose terminal point, $\left(-\dfrac13,y\right)$ lies on the circle $x^2+y^2=1$ . The $x$ -coordinate is all we need to know in order to find that $\cos\beta=-\dfrac13$ . So,

$\sin\dfrac\beta2=\sqrt{\dfrac{1-\left(-\frac13\right)}2}=\sqrt{\dfrac46}=\dfrac{\sqrt2}{\sqrt3}=\dfrac{\sqrt6}3$

6 0

3 years ago