A large cargo ship dropped anchor in the ocean. The anchor was released at a constant rate rate of speed from a height of 44 met
1 answer:
Answer:
C and E
Step-by-step explanation:
The change in elevation was 44 + 20 = 64 m
the rate of fall was 64 m / 32 s = 2 m/s
The anchor reached the surface in 44 / 2 = 22 s so C is valid
E is correct as the ocean surface is origin and <u>Up</u> is the positive direction.
The anchor starts at 44 m above the surface and position is lower by 2 meters every second
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