100 minus 47.3 equals 52.7
Answer:the number of adult tickets that were sold is 321
the number of adult tickets that were sold is 227
Step-by-step explanation:
Let x represent the number of adult tickets that were sold.
Let y represent the number of adult tickets that were sold.
Regal theater in Tikahtnu sold 548 tickets to Moana on Sunday. This means that
x + y = 548
A adult's ticket was $6.50 while a child's ticket was $3.50. In total, they took in $2881 in sales of these ticket. This means that
6.5x + 3.5y = 2881 - - - - - - - - -1
Substituting x = 548 - y into equation 1, it becomes
6.5(548 - y) + 3.5y = 2881
3562 - 6.5y + 3.5y = 2881
- 6.5y + 3.5y = 2881 - 3562
- 3y = - 681
y = - 681/-3 = 227
Substituting y = 227 into x = 548 - y, it becomes
x = 548 - 227 = 321
For this case we must find the value of the variable "x" of the following equation:
We multiply by 3 on both sides of the equation:
We divide between 2 on both sides of the equation:
We subtract 7 on both sides of the equation:
Answer:
Option B
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.
The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151
Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.
Hope this makes sense.
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Answer:
Null hypothesis:
Alternative hypothesis:
The statistic would be given by:
(1)
Now we need to find the critical value for the rejection zone of the null hypothesis. Since we have a left tailed test we need to find in the normal standard distirbution a value who accumulate 0.05 of the area in the left tail and we got:
And the best choice for this case would be:
z < − 1.65
Step-by-step explanation:
Information provided
n=2431 represent the random sample taken
estimated proportion of interest
is the value that we want to test
represent the significance level
Confidence=95% or 0.95
z would represent the statistic
Hypothesis to test
We want to verify if the true proportion of Americans who reduced meat consumption last year is less than 0.25, then the system of hypothesis are :
Null hypothesis:
Alternative hypothesis:
The statistic would be given by:
(1)
Now we need to find the critical value for the rejection zone of the null hypothesis. Since we have a left tailed test we need to find in the normal standard distirbution a value who accumulate 0.05 of the area in the left tail and we got:
And the best choice for this case would be:
z < − 1.65