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3 years ago

Write an equation in Slope-Intercept Form using the table below.

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

Answer:

y = x + 46

Step-by-step explanation:

When writing an equation of a line, keep in mind that you always need the following information in order to determine the linear equation in slope-intercept form, y = mx + b:

1. 2 sets of ordered pairs (x, y)

2. Slope (m)

3. Y-intercept (b)

First, choose two pairs of coordinates to use for solving the slope of the line:

Let (x1, y1) = (0, 46)

(x2, y2) = (1, 47)

User the following formula for slope

$m = \frac{y2 - y1}{x2 - x1}$

Plug in the values of the coordinates into the formula: $m = \frac{y2 - y1}{x2 - x1} = \frac{47 - 46}{1 - 0} = \frac{1}{1} = 1$

Therefore, the slope (m) = 1.

Next, we need the y-intercept, (b). The y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0. The y-coordinate of the point (0, 46) is the y-intercept. Therefore, b = 46.

Given the slope, m = 1, and y-intercept, b = 46, the linear equation in slope-intercept form is:

y = x + 46

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<u>Given</u>:

Given that Corey is flying a kite with 105 meters of string.

The string makes an angle of 42° with the ground level.

We need to determine the height of the kite.

<u>Height of the kite: </u>

The height of the kite can be determined using the trigonometric ratio.

Thus, we have;

$sin \ \theta=\frac{opp}{hyp}$

From the given data, the values are $\theta=42^{\circ}$ , opp = h (height of the kite) and hyp = 105 meters.

Substituting the values, we get;

$sin \ 42=\frac{h}{105}$

Multiplying both sides of the equation by 105, we get;

$sin \ 42 \times 105=h$

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3 years ago

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Answer:

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Step-by-step explanation:

Given

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Step-by-step explanation:

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3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

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3 years ago

Write an equation in Slope-Intercept Form using the table below. ​

Write an equation in Slope-Intercept Form using the table below.