Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
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Answer:
(3,4) because only the y would change when it is being reflected over the x axis :)
Step-by-step explanation:
9514 1404 393
Answer:
3. 7
Step-by-step explanation:
The distance formula applies in 3 dimensions as well as 2.
d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)
d = √((-2)² +6² +3²) = √(4 +36 +9) = √49
d = 7
The distance between the two points is 7 units.
