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IceJOKER [234]
3 years ago
5

Make a stem-and-leaf plot for the following data. 59, 38, 33, 26, 44, 35, 32, 47, 45, 24, 27, 46, 34, 30, 36

Mathematics
2 answers:
aliina [53]3 years ago
7 0
Stem :          leaf :
  2                 4,6,7
  3                 0,2,3,4,5,6,8
  4                 4,5,6,7
  5                 9

Shkiper50 [21]3 years ago
5 0

Answer:

Stem        Leaf

 2             4 6 7

 3             0 2 3 4 5 6 8

 4             4 5 6 7

 5             9

Step-by-step explanation:

Stem-and-leaf plot is a tabular form of representing a set of data where the data values are split into a "stem" (the first digit of the number) and "leaf" (the last digit of the number).

For example: 59 can be written as

Stem        Leaf

5                  9

For the data 59, 38, 33, 26, 44, 35, 32, 47, 45, 24, 27, 46, 34, 30, 36.

The stem-and-leaf plot is:

Stem        Leaf

 2             4 6 7

 3             0 2 3 4 5 6 8

 4             4 5 6 7

 5             9

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Fynjy0 [20]
A and F are the only set of ordered pairs that work in both of the equations above. 

 In order to find these you must place them into each equation and check for truth. Below is the work for A and F. 

Ordered Pair A : (0,6)

y > 6x + 5
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6 > 5 (TRUE)

y < -6x + 7
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6 < 7 (TRUE)

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7 0
3 years ago
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Find the measures of
Yuki888 [10]

Answer:

Step-by-step explanation:

Measure of an inscribed angle intercepted by an arc is half of the measure of the arc.

From the picture attached,

m(∠A) = \frac{1}{2}m(\text{arc BD})

           = \frac{1}{2}[m(\text{BC})+m(\text{CD}]

           = \frac{1}{2}[55^{\circ}+145^{\circ}]

           = 100°

m(∠C) = \frac{1}{2}[(360^{\circ})-m(\text{arc BCD})]

           = \frac{1}{2}(360^{\circ}-200^{\circ})

           = 80°

m(∠B) + m(∠D) = 180° [ABCD is cyclic quadrilateral]

115° + m(∠D) = 180°

m(∠D) = 65°

m(arc AC) = 2[m(∠D)]

m(arc AB) + m(arc BC) = 2(65°) [Since, m(arc AC) = m(arc AB) + m(arc BC)]

m(arc AB) + 55° = 130°

m(arc AB) = 75°

m(arc ADC) = 2(m∠B)

m(arc AD) + m(arc DC) = 2(115°)

m(arc AD) + 145° = 230°

m(arc AD) = 85°

7 0
3 years ago
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