Answer:
<h3>First line has y intercept -2 ( the blue line ) </h3><h3>Second line has y intercept 3 ( the red line )</h3><h3>The point where these two lines cross is "D"</h3>
A and F are the only set of ordered pairs that work in both of the equations above.
In order to find these you must place them into each equation and check for truth. Below is the work for A and F.
Ordered Pair A : (0,6)
y > 6x + 5
6 > 0 + 5
6 > 5 (TRUE)
y < -6x + 7
6 < 0 + 7
6 < 7 (TRUE)
Ordered Pair F : (-2, 18)
y > 6x + 5
18 > - 12 + 5
18 > -7 (TRUE)
y < -6x + 7
18 < 12 + 7
18 < 19 (TRUE)
Answer:
Step-by-step explanation:
Measure of an inscribed angle intercepted by an arc is half of the measure of the arc.
From the picture attached,
m(∠A) = 
= ![\frac{1}{2}[m(\text{BC})+m(\text{CD}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7BBC%7D%29%2Bm%28%5Ctext%7BCD%7D%5D)
= ![\frac{1}{2}[55^{\circ}+145^{\circ}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B55%5E%7B%5Ccirc%7D%2B145%5E%7B%5Ccirc%7D%5D)
= 100°
m(∠C) = ![\frac{1}{2}[(360^{\circ})-m(\text{arc BCD})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%28360%5E%7B%5Ccirc%7D%29-m%28%5Ctext%7Barc%20BCD%7D%29%5D)
= 
= 80°
m(∠B) + m(∠D) = 180° [ABCD is cyclic quadrilateral]
115° + m(∠D) = 180°
m(∠D) = 65°
m(arc AC) = 2[m(∠D)]
m(arc AB) + m(arc BC) = 2(65°) [Since, m(arc AC) = m(arc AB) + m(arc BC)]
m(arc AB) + 55° = 130°
m(arc AB) = 75°
m(arc ADC) = 2(m∠B)
m(arc AD) + m(arc DC) = 2(115°)
m(arc AD) + 145° = 230°
m(arc AD) = 85°