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kupik [55]
3 years ago
13

Joey, Chloe and Haddie are driving go-carts around a track. Joey takes 14 minutes, Chloe takes 12 minutes and Haddie takes 10 mi

nutes to drive one lap. Suppose all three left the starting line at 8:15AM and drove at a constant speed. At what time will all three meet again?
Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

3:15PM


The LCM of 10 12 and 14 is 420

420÷60=7

7 Hours after 8:15AM is 3:15PM


The LCM (Least Common Multiple) of two numbers is the smallest number that is a multiple of both.

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5 If 15 cookies cost $8.50, how much would it cost for 25 cookies? Write a proportion and solve it below:​
AlladinOne [14]

Answer:

14.25

Step-by-step explanation:

8.5/15=0.57

1:0.57

0.57*25=14.25

6 0
2 years ago
You are making a banner. You have a sheet of paper that is 2 m wide and want to leave a 35-cm blank margin on either side. How m
Dennis_Churaev [7]
<span>100 cm = 1 meter.
Ok you have 200 cm of paper. Each side needs 35 cm for a margin so:
35 + 35 = 70.
Then subtract 70 from 200 and you are left with 130 cm of space left for text.</span>
7 0
3 years ago
Solve each compound inequality. Graph your solutions.<br> 5 + m &gt; 4 or 7m&lt; -35
Yuliya22 [10]

Answer:

Solving the inequality 5 + m > 4\: or\: 7m< -35 we get \mathbf{m>-1\:or\: \:m

The graph of the inequality is shown in figure attached.

Step-by-step explanation:

We need to Solve each compound inequality 5 + m > 4\: or\: 7m< -35

Solving the inequalities

For solving compound inequalities we solve both inequalities simultaneously and find the value of m.

For solving 5+m > 4, we subtract 5 from both sides.

While solving 7m < -35, we divide both sides by 7 to get value of m

Applying these functions we get:

5 + m > 4\: or\: 7m< -35\\m>4-5\:or\:m-1\:or\:m

So, solving the inequality 5 + m > 4\: or\: 7m< -35 we get \mathbf{m>-1\:or\: \:m

The graph of the inequality is shown in figure attached.

5 0
3 years ago
What is the solution of the equation?
elena-s [515]

Answer:

Step-by-step explanation:

its c=5

6y+18+3=51

6y+21=51

6y=51-21

6y=30

y=5

4 0
3 years ago
Read 2 more answers
Find a three digit number. The tens digit is 3 time the hundreds digit. The sum of the digits is 15. If you reverse the digits,
tresset_1 [31]

Answer:

number = 267

Step-by-step explanation:

i am a 3 digit number divisible by 3.

100a + 10b + c

my tens digit is 3 times as great as my hundreds digit

b = 3a, from this we know a = 1, 2, 3, then b = 3, 6, 9

and the sum of my digits is 15.

a + b + c = 15

if you reverse my digits i am divisible by 6 and 3

100c + 10b + a

this is a logic problem, an equation won't help us here

From the given information b = 3a, and the sum of the 3 digits = 15, we have:

1 3 ___; three single digits can't add up to 15

2 6 _7_; this has to be the number

3 9 _3_; reverse number is not different

Check for division by 3 and 6

267/3 = 89

762/6 = 127

267 is the number

3 0
3 years ago
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