Joey, Chloe and Haddie are driving go-carts around a track. Joey takes 14 minutes, Chloe takes 12 minutes and Haddie takes 10 mi
nutes to drive one lap. Suppose all three left the starting line at 8:15AM and drove at a constant speed. At what time will all three meet again?
1 answer:
3:15PM
The LCM of 10 12 and 14 is 420
420÷60=7
7 Hours after 8:15AM is 3:15PM
The LCM (Least Common Multiple) of two numbers is the smallest number that is a multiple of both.
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