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kupik [55]
3 years ago
13

Joey, Chloe and Haddie are driving go-carts around a track. Joey takes 14 minutes, Chloe takes 12 minutes and Haddie takes 10 mi

nutes to drive one lap. Suppose all three left the starting line at 8:15AM and drove at a constant speed. At what time will all three meet again?
Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

3:15PM


The LCM of 10 12 and 14 is 420

420÷60=7

7 Hours after 8:15AM is 3:15PM


The LCM (Least Common Multiple) of two numbers is the smallest number that is a multiple of both.

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Fred bought 4 liters of liquid laundry detergent 3250 mL of fabric softener and 2.5 L of bleach which date that is true
Colt1911 [192]
The complete question in the attached figure

we know that

<span>Fred bought
</span><span>4 liters of liquid laundry detergent 
</span><span>3250 mL of fabric softener------------> 3250/1000-------> 3.25 liters
</span><span>2.5 L of bleach-----------> 2.5 liters

then
</span><span>statements

4a. Fred bought 75 milliliters more fabric softener than bleach
</span>3.25-2.5-------> 0.75 liters--------> 750 mi
the statement is false

<span>4b. Fred brought 1.75 liters more laundry detergent than bleach
4-2.5---------> 1.5 liters
</span>the statement is false

4c. Fred brought 750 milliliters more fabric softener than bleach. <span>
3.25-2.5-------> 0.75 liters-------> 750 ml
</span>the statement is true

4d. Fred brought 150 milliliters more laundry detergent than bleach.
4-2.5--------> 1.5 liters---------> 1500 ml
the statement is false

<span>4e. Fred bought 0.75 liters more laundry detergent than fabric softener.
</span>4-3.25--------> 0.75 liters
the statement is true

4 0
4 years ago
The formula for the size of a file that was downloaded over time t and at an average rate r is r.t.
lakkis [162]

Answer:

The size of file downloaded is  <em>88 megabytes.</em>

Step-by-step explanation:

Given that:

Average rate of downloading the file = r

Time taken to download = t

Formula for the size of file downloaded = r.t

Rate of downloading, r = 800\ kilobytes/sec

Time taken, t = 110 seconds

To find:

Size of file downloaded in megabytes = ?

Solution:

First of all, let us apply the given formula to find the size of file downloaded:

Size of file downloaded = r.t

Size of file downloaded = 800 kilobytes seconds \times 110 seconds =

<em>88000 kilobytes</em>.

Now, let us convert the unit kilobytes to megabytes to find the answer.

<em>Conversion formula:</em>

1000 kilobytes = 1 megabyte

Let us use unitary method to find the number of megabytes in 88000 kilobytes.

1 kilobytes = \frac{1}{1000} megabytes

88000 kilobytes = \frac{1}{1000} \times 88000 megabytes

\Rightarrow <em>88 megabytes.</em>

Therefore, the size of file downloaded is  <em>88 megabytes.</em>

5 0
3 years ago
The ratio x : 8 is equivalent to the ratio 8 : x^2. What is the value of x?
dimulka [17.4K]

Answer:

x=1

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Two addends
nataly862011 [7]

Answer:

28

Step-by-step explanation:

18+6+4=28

8 0
3 years ago
A population has the following characteristics. (a) A total of 75% of the population survives the first year. Of that 75%, 25% s
Artemon [7]

Answer:

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age  \leq 3}\end{array}\right

i.e after the first year ;

there 1344 members in the first age class

84 members for the second age class; and

28 members for the third age class

Step-by-step explanation:

We can deduce that the age distribution vector x represents the number of population members for each age class; Given that in each class of age there are 112 members present.

The current age distribution vector is as follows:

x = \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right] \left[\begin{array}{ccc}{0 \  \leq  age   \leq  1 }\\{ 0 \  \leq  age   \leq  2 }\\{0 \  \leq  age   \leq 3}\end{array}\right]

Also , the age transition matrix is as follows:

L = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]

After 1 year ; the age distribution vector will be :

x_2 =Lx_1 = \left[\begin{array}{ccc}3&6&3\\0.75&0&0 \\0&0.25&0\end{array}\right]  \left[\begin{array}{ccc}1&1&2\\1&1&2\\1&1&2\end{array}\right]

= \left[\begin{array}{ccc}1344\\84\\28\end{array}\right]  \left \begin{array}{ccc}{0 \  \leq  age   \leq 1 }\\{ 1 \  \leq  age   \leq  2 }\\{2 \  \leq  age   \leq  3}\end{array}\right

6 0
3 years ago
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