Answer:
There are two x-intercepts.
A quadratic function whose maximum degree two. Therefore, Total two x-intercept possible.
We are given the range of quadratic function y less than equal to 2. It means parabola is downward whose maximum value 2.
Here y is greater than 2 and parabola form downward. Here must be two x-intercept.
If a>0 then form open up parabola.
If a<0 then open down parabola.
Here open down parabola. So, we get total two x-intercept.
Please see the attachment for diagram.
Answer:
i think 4
Step-by-step explanation:
![x^{2} +4x-3](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B4x-3)
Answer:
(x+1)^2+(y-7)^2=8
Step-by-step explanation:
You should try the next one and I can check work or tell you if it is right.
The diameter length can be found be computing the distance that (-3,5) is to (1,9) which is sqrt(4^2+4^2)=sqrt(32).
The radius is half the diameter so it is sqrt(32)/2.
The center of the circle is the midpoint of a diameter. So compute the (Average of x, average of y)=(-1,7)
So plug into (x-h)^2+(y-k)^2=r^2 we get
(x+1)^2+(y-7)^2=32/4
simplifying gives
(x+1)^2+(y-7)^2=8
(I had to type this twice; my cat jump on my keyboard)
Answer:
x = √30 or -√30
Step-by-step explanation:
480 - 16x^2 = 0
divide both sides by 16
30 - x^2 = 0
-x^2 + 30 = 0
-x^2 = -30
X^2 = 30
x = ± √30
x = √30 or -√30
Answer:
-12
Step-by-step explanation:
you have to divide 48 to (-4) and it equals to -12
so you multiply -12 to (-4) and it gives you 48